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adelina 88 [10]
3 years ago
12

The largest aperture telescopes are reflectors because they require a _____ focal length.

Physics
1 answer:
Stells [14]3 years ago
5 0
The largest aperture telescopes are reflectors because they require a shorter focal length. I think that is the answer! I hope that it helps!
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What do Oxygen and Fluorine do to do Copper?
Evgen [1.6K]
It corrodes the copper by oxydation
4 0
3 years ago
If the vertical component of velocity for a projectile is 7.3 meters/second, what is its hang time?
Kamila [148]
A projectile motion is characterized by motion moving in a direction of an arc. It is acted upon by two component vectors: the horizontal and vertical. These two vectors are independent of each other when it comes to time of flight. The horizontal direction travels at constant speed, while the vertical direction travels at constant acceleration due to gravity, The time for an object to reach the ground would be equal, whether dropped from the sampe point or thrown in a projectile motion. Of course, this is assuming ideality wherein there is no air resistance.

So, the hang up time, or the time the object stayed on air is calculated using this equation:

a = Δv/t
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9.81 m/s² = |(0 - 7.3)|/t
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6 0
3 years ago
What is the kinetic energy in joules of a 0.05. kg bullet traveling 310 m/s
Wittaler [7]
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3 0
3 years ago
If 0.035pC of charge is transferred via the movement of Al3+ ions, how's many of these must be transferred in total? Please add
mr Goodwill [35]

Each Al^+^3 ion contains three extra protons. Hence, the extra charge on each  Al^+^3 = 3 \times 1.6 \times 10^-^1^9 C

Total charge = 0.035 pC

Total charge (Q) = 0.035 \times 10^-^1^2 C

Let the number of Al^+^3 ions be n.

According to question:

n \times 3 \times 1.6 \times 10^-^1^9 =0.035 \times 10^-^1^2

n = \frac{0.035 \times 10^-^1^2}{3 \times 1.6 \times 10^-^1^9}

n = 7.29167 \times 10^4

n = 72917

Hence, the total number of ions needed to be transferred is 72917

3 0
3 years ago
3.25 kcal is the same amount of energy as
PIT_PIT [208]
<span>1 cal = 4,185 J
1 kcal = 1*10^3 cal
or
=1000 cal</span>
8 0
3 years ago
Read 2 more answers
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