Here is the answer for the three of them
<span>N20 = 16 e-
</span><span>SeCl2 =20
</span><span>PBr3 = 26
Remember that t</span><span>o find the valence electrons in an atom you need to identify what group the element is in. An element in group 1A has 1 valence electron. If the element is in group 2A, then it has two valence electrons.</span>
Answer:
Explanation:
A) O2 (non polar covalent)
B) HF (polar covalent)
C) NaCl (because its ionic)
im not 100% sure hope it helps
The answer is B. The density, or more precisely, the volumetric mass density, of a substance is its mass per unit volume.
Answer : The activation energy for the reaction is, 51.9 kJ
Explanation :
According to the Arrhenius equation,

or,
![\log (\frac{K_2}{K_1})=\frac{Ea}{2.303\times R}[\frac{1}{T_1}-\frac{1}{T_2}]](https://tex.z-dn.net/?f=%5Clog%20%28%5Cfrac%7BK_2%7D%7BK_1%7D%29%3D%5Cfrac%7BEa%7D%7B2.303%5Ctimes%20R%7D%5B%5Cfrac%7B1%7D%7BT_1%7D-%5Cfrac%7B1%7D%7BT_2%7D%5D)
where,
= rate constant at 295 K
= rate constant at 305 K = 
Ea = activation energy for the reaction = ?
R = gas constant = 8.314 J/mole.K
= initial temperature = 295 K
= final temperature = 305 K
Now put all the given values in this formula, we get:
![\log (\frac{2K_1}{K_1})=\frac{Ea}{2.303\times 8.314J/mole.K}[\frac{1}{295K}-\frac{1}{305K}]](https://tex.z-dn.net/?f=%5Clog%20%28%5Cfrac%7B2K_1%7D%7BK_1%7D%29%3D%5Cfrac%7BEa%7D%7B2.303%5Ctimes%208.314J%2Fmole.K%7D%5B%5Cfrac%7B1%7D%7B295K%7D-%5Cfrac%7B1%7D%7B305K%7D%5D)

Therefore, the activation energy for the reaction is, 51.9 kJ