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tatyana61 [14]
3 years ago
8

Reproductive cells contain only _____ gene copy.

Chemistry
1 answer:
lions [1.4K]3 years ago
5 0

Answer:

Reproductive cells contain only four gene copy.

Explanation:

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PLEASE HELP! I DONT KNOW WHAT TO DO! ITS ALOT PLEASE HELP THO!
kirza4 [7]

Answer:

CuCl2 (aq) + (NH4)2CO3(aq) → NH4Cl(aq) + CuCO3(s)

* CuCl2 (aq) + (NH4)2CO3(aq) → 2NH4Cl(aq) + CuCO3(s)

*Cu(2+)(aq)+ 2Cl(-)(aq) + 2NH4(+)(aq) + CO3(2-)(aq) →2NH4(+)(aq) + Cl(-)(aq) + CuCO3(s)

*Cu(2+)(aq)+ CO3(2-)(aq) → CuCO3(s)

*2HCl(aq) + 2MgCO3(s) → 2MgCl(aq) + H2O(l) + 2CO2(g)

* 2H(+)(aq) + 2Cl(-)(aq) + 2MgCO3(s) → 2Mg(2+)(aq) +2Cl(-) (aq) + H2O(l) + 2CO2(g)

* 2MgCO3(s) → 2Mg(2+)(aq) + H2O(l) + 2CO2(g)

*ZnCl2(aq) + 2AgC2H3O2(aq) → 2AgCl(s) + Zn(C2H3O2)2(aq)

*Zn(2+)(aq) + 2Cl(-)(aq) + 2Ag(+)(aq) + C2H3O2(-)(aq) → 2AgCl(s) + Zn(2+)(aq) 2C2H3O2(-)(aq)

*2Cl(-)(aq) + 2Ag(+)(aq)  → 2AgCl(s)

*MnO(s) + H2SO4(aq) → MnSO4(s) + H2O (l)

*MnO(s) + 2H(+)(aq) + SO4(2-)(aq) → MnSO4(s) + H2O (l)

*MnO(s) + 2H(+)(aq) + SO4(2-)(aq) → MnSO4(s) + H2O (l)

*FeS(s) + 2HCl (aq) → FeCl2(aq) + H2S(g)

*FeS(s) + 2H(+)(aq) + 2Cl(-)(aq)  → Fe(2+)(aq)+ 2Cl(-)(aq)) + H2S(g)

*FeS(s) + 2H(+)(aq)  → Fe(2+)(aq)+ H2S(g)

Explanation:

In the first equation you only need to know the rules of solubility. All chlorides are solubles  except Ag+ Pb+2 and Hg2(2+) and most carbonates are insolubles

<em>For ionic equations</em> Start with a balanced molecular equation.  Break all soluble strong electrolytes (compounds with (aq) beside them) into their ions  indicate the correct formula and charge of each ion . Indicate the correct number of each ion  and write (aq) after each ion . Bring down all compounds with (s), (l), or (g) unchanged.

<em>For net ionic equations </em>Write the balanced molecular equation.  Write the balanced complete ionic equation.  Cross out the spectator ions that are present.  Write the "leftovers" as the net ionic equation.

Before this, te equation must be balanced.

* CuCl2 (aq) + (NH4)2CO3(aq) → 2NH4Cl(aq) + CuCO3(s)

*Cu(2+)(aq)+ 2Cl(-)(aq) + 2NH4(+)(aq) + CO3(2-)(aq) →2NH4(+)(aq) + Cl(-)(aq) + CuCO3(s)

*Cu(2+)(aq)+ CO3(2-)(aq) → CuCO3(s)

*2HCl(aq) + 2MgCO3(s) → 2MgCl(aq) + H2O(l) + 2CO2(g)

* 2H(+)(aq) + 2Cl(-)(aq) + 2MgCO3(s) → 2Mg(2+)(aq) +2Cl(-) (aq) + H2O(l) + 2CO2(g)

* 2MgCO3(s) → 2Mg(2+)(aq) + H2O(l) + 2CO2(g)

*ZnCl2(aq) + 2AgC2H3O2(aq) → 2AgCl(s) + Zn(C2H3O2)2(aq)

*Zn(2+)(aq) + 2Cl(-)(aq) + 2Ag(+)(aq) + C2H3O2(-)(aq) → 2AgCl(s) + Zn(2+)(aq) 2C2H3O2(-)(aq)

*2Cl(-)(aq) + 2Ag(+)(aq)  → 2AgCl(s)

*MnO(s) + H2SO4(aq) → MnSO4(s) + H2O (l)

*MnO(s) + 2H(+)(aq) + SO4(2-)(aq) → MnSO4(s) + H2O (l)

*MnO(s) + 2H(+)(aq) + SO4(2-)(aq) → MnSO4(s) + H2O (l)

*FeS(s) + 2HCl (aq) → FeCl2(aq) + H2S(g)

*FeS(s) + 2H(+)(aq) + 2Cl(-)(aq)  → Fe(2+)(aq)+ 2Cl(-)(aq)) + H2S(g)

*FeS(s) + 2H(+)(aq)  → Fe(2+)(aq)+ H2S(g)

7 0
3 years ago
What is the sum of 2.7 g and 2.47g expressed in the correct number of significant digits
NeTakaya
In order to get the sum of 2.7 and 2.47, we will add both numbers. So, 2.7 plus 2.47 would be 5.17. And the correct number of significant digits in this number is still the same, 5.17, so we have three significant numbers. Why? There are three rules in identifying the significant figures: 1. Non zeros are always significant (which this applies in our sum above). 2. Any zeros in between significant numbers are always significant. 3. <span> The final zero or zeros in the decimal portion only are significant.</span>
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2 years ago
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alexdok [17]

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NaCl, we have 3.0 moles of Na+.
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