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tatyana61 [14]
3 years ago
8

Reproductive cells contain only _____ gene copy.

Chemistry
1 answer:
lions [1.4K]3 years ago
5 0

Answer:

Reproductive cells contain only four gene copy.

Explanation:

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What is the period of a wave with a frequancy of 3 Hz and an amplitude off 0.01
lara31 [8.8K]

0.33 seconds is the period of a wave with a frequency of 3 Hz and an amplitude off 0.01 .

<u>Explanation:</u>

We have , period of a wave with a frequency of 3 Hz and an amplitude off 0.01 . We know that period of a wave is amount of time needed to complete one oscillation . In order to calculate period of wave we use frequency and the formula use is period = \frac{1}{frequency} . We are given that frequency = 3 Hz:

period = \frac{1}{frequency}

⇒ period = \frac{1}{frequency}

⇒ period = \frac{1}{3 Hz}

⇒ period = 0.33 seconds

Therefore, 0.33 seconds is the period of a wave with a frequency of 3 Hz and an amplitude off 0.01 .

4 0
3 years ago
Explain the various modes of dispersal of seeds and fruits.​
11Alexandr11 [23.1K]
There are five main modes of seed dispersal: gravity, wind, ballistic, water, and by animals. Some plants are serotinous and only disperse their seeds in response to an environmental stimulus. Dispersal involves the letting go or detachment of a diaspore from the main parent plant.

Fruits and seeds dispersal is the process whereby fruits and seeds are scattered from their origin. The various ways by which fruit and seed are dispersed are known as agents of seed and fruit dispersal.

Check this link out for more information
https://qknowbooks.gitbooks.io/fruits-and-seeds/content/fruits_and_seeds_dispersal.html
4 0
3 years ago
Use the equation editor or "Insert Chemistry - WIRIS editor" to write the balanced molecular chemical equation for the reaction
11Alexandr11 [23.1K]

Answer:

<u>Balanced equation:</u>

Pb(NO_{3})_{2}(aq)+K_{2}CO_{3}(aq)\rightarrow PbCO_{3}(s)+2KNO_{3}(aq)

Explanation:

The chemical reaction between Lead(II) Nitrate and potassium carbonate is as follows.

Lead(II)Nitrate+Potassium\,carbonate \rightarrow Lead(III)\,\,carbonate+Potassium\,nitrate

Pb(NO_{3})_{2}(aq)+K_{2}CO_{3}(aq)\rightarrow PbCO_{3}(s)+2KNO_{3}(aq)

<u>Ionic equation:</u>

Pb^{2+}(aq)+2NO_{3}^{-}(aq)+2K^{+}(aq)+CO_{3}^{2-}(aq)\Leftrightarrow PbCO_{3}(s)+K^{+}(aq)+2NO_{3}^{-}

Cancel the same ions on the both sides of the reaction.

The net ionic equation is as follows.

Pb^{2+}(aq)+CO_{3}^{2-}(aq)\Leftrightarrow PbCO_{3}(s)

4 0
3 years ago
Can you balance 12 blocks on the 3x2 platform
Jobisdone [24]
Yes, it is possible to go do because it would be 2 stacks of 6
3 0
2 years ago
Identify each statement as true or false. Explain in every case.a.Ionization energies are always negative quantities.b.Oxygen ha
worty [1.4K]

Answer:

(a) FALSE

(b) FALSE

(c) TRUE

(d) FALSE

Explanation:

Ionization energy refers to the energy needed for removal of a valence electron present in valence shell of a gaseous atom.

(a) <u>The value of ionization energy of an atom is always</u><u> positive</u>. This is because energy has to be always supplied or provided to a gaseous atom for the removal of the valence electron.

<em><u>Therefore, the statement (A) is</u></em><em><u> false</u></em>

   

(b) The ionization energy of an atom <u>increases across a period</u> i.e. from left to right. This is because the <u>effective nuclear charge that is experienced by the valence electron increases</u> from left to right in the periodic table, as the atomic number increases.

So, more energy is required to remove the valence electron of fluorine as compared to oxygen.

<u>Therefore, the </u><u>ionization energy of fluorine is greater than oxygen</u><u>.</u>

<em><u>Therefore, the statement (B) is</u></em><em><u> false</u></em>

(c) <u>First ionization energy</u> is energy needed for removal of first electron present in valence shell of a neutral atom. Whereas, <u>second ionization energy</u> is the energy needed for removal of second electron present in valence shell of a monovalent cation

The second ionization energy of an atom is always greater than the first ionization energy. This is because removing<u> an electron from a positively charged species, requires more energy.</u>

<em><u>Therefore, the statement (C) is</u></em><em><u> true</u></em>

<em><u /></em>

(d) <u>The third ionization energy </u>refers to the energy needed to remove the third electron from a divalent cation.

<em><u>Therefore, the statement (D) is</u></em><em><u> false</u></em>

7 0
3 years ago
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