Answer: B. 100 Hz
Explanation:
Here, the frequency for the standing-wave modes of a tube is given as
f(n)= m*f
For first frequency put f= 20 Hz, m=1
So f₁= 1*20= 20Hz
The next resonance occurs at m=3
f₂= 3*20= 60 Hz
So meaning at odd intervals the resonance occurs so next will occur at m=5
So,
f₃= 5*20= 100 Hz
So, option B. 100 Hz is correct.
The two forces are 12N and 10N (option B)
<h3>What is the net force?</h3>
The net force is the force that has the same effect in magnitude and direction as the two forces acting together.
This problem can be solved using a right angled triangle;
Let the forces be P and Q
sin 40 = P/16
P= 16 sin 40
P = 10 N
Cos 40 = Q/16
Q = 16 cos 40
Q = 12 N
Learn more about resultant force:brainly.com/question/16380983
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To continue moving at constant speed in a straight line requires NO net force. Zero. Nada. If there IS any net force on the object, then its speed or direction will change.
I believe It's either a supernova or a planetary nebula.
Answer:
2
Explanation:
İf system ideal ( no frictional force )
Fnet=m.a
20=10.a
a=2m/s2