3 years ago

A girl pulls on a 10 kg wagon with a constant force of 20 N. What is the wagon’s acceleration

Physics

1 answer:

andreev551 [17]3 years ago

6 0

Answer:

Explanation:

İf system ideal ( no frictional force )

Fnet=m.a

20=10.a

a=2m/s2

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A uniform disk of mass M = 4.9 kg has a radius of 0.12 m and is pivoted so that it rotates freely about its axis. A string wrapp

AlekseyPX

Answer:

(A) 2.4 N-m

(B) $0.035kgm^2$

(D) 1741.13 J

(E) 725.481 rad

Explanation:

We have given mass of the disk m = 4.9 kg

Radius r = 0.12 m, that is distance = 0.12 m

Force F = 20 N

(a) Torque is equal to product of force and distance

So torque $\tau =Fr$ , here F is force and r is distance

So $\tau =20\times 0.12=2.4Nm$

(B) Moment of inertia is equal to $I=\frac{1}{2}mr^2$

So $I=\frac{1}{2}\times 4.9\times 0.12^2=0.035kgm^2$

Torque is equal to $\tau =I\alpha$

So angular acceleration $\alpha =\frac{\tau }{I}=\frac{2.4}{0.035}=68.571rad/sec^2$

So initial angular speed $\omega _{0}=0rad/sec$

Time t = 4.6 sec

From first equation of motion we know that $\omega =\omega _0+\alpha t$

So $\omega =0+68.571\times 4.6=315.426rad/sec$

(D) Kinetic energy is equal to $KE=\frac{1}{2}I\omega ^2=\frac{1}{2}\times 0.035\times 315.426^2=1741.13J$

(E) From second equation of motion

$\Theta =\omega _0t+\frac{1}{2}\alpha t^2=0\times 4.6+\frac{1}{2}\times 68.571\times 4.6^2=725.481rad$

3 0

3 years ago

A TV with a power rating of 267 W uses 1.9 kWh in one day. How many hours was the TV during that day?

Aleonysh [2.5K]

1.9kWh/0.267kW = 7.11 hours

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3 years ago

when arti kicks a football two forces interact, arti's foot exerts a force of 5N on the ball. what size force will be exerted on

CaHeK987 [17]

Answer:

F=MA

5N=M×10M/SQ.

1/2 KG. =MASS

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3 years ago

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Every 6 seconds a pendulum completes 1 cycle. What are the period and frequency of this pendulum?

Kruka [31]

Multiply 6 x 60 to get the frequency.

8 0

3 years ago

Plz help me it is improtant

marishachu [46]

I think it is b cause I don’t think you do that

7 0

3 years ago