Answer:
The capacitance is 11 F for half and fully charged capacitor.
Explanation:
Capacitance of capacitor is given by the expression
Where ε is the vacuum permittivity, A is the area of plates and d is the separation between plates.
So capacitance does not depend upon charge and potential. So capacitance fully and half charged capacitors are same.
Here the capacitance is 11 F for half and fully charged capacitor.
Answer:
v/U=0.79
Explanation:
Given u=
Now for the given flow to be possible it should satisfy continuity equation
Applying values in this equation we have
Thus we have
Hence proved
For maximum value of v/U put y =
Thus solving we get using the given values
v/U=0.79
Answer:
The energy dissipate at a rate of 11.34 W when the resistor is connected between the terminals of a 1.50 V battery.
Explanation:
the rate at which energy dissipeted is given by power and we know that when given resistance, R and voltage, V then power is given by:
P = V^2/R
R = V^2/P
= (3.00)^2/(0.560)
= 5.04 ohms
then when the resistor is now connected between the terminals of a 1.50 V battery, then the power is given by:
P = V^2/R
= (1.50)^2/(5.40)
= 11.34 W.
Therefore, the energy dissipate at a rate of 11.34 W when the resistor is connected between the terminals of a 1.50 V battery.
Answer:
2940.1 joules would you burn in climbing stairs all day.
Explanation:
Work = W = F d
going up stairs would be against force of gravity
W = mgh
where h is the height
the question is not complete because we need speed or distance
h = v t
so assuming 1 step per second
h = 86,400 steps 7inchs/step 0.0254 m/inch
h = 15362 m
so from this
W = 800 N 15362
= 12289600 J
that means YOU need 12289600 J to walk 1 step per second all day
divide that by 4180 J /Kcal
Kcal =
=
= 2940.1 Kcal
if you ran faster you would use more energy 2 steps per second would mean 5880 Kcal.
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