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barxatty [35]
3 years ago
6

A tire has a tread pattern with a crevice every 2.00 cm. The repetitive striking of the crevice edges on the road results in a v

ibration as the tire moves. What is the frequency of these vibrations if the car moves at 14.4 m/s?
Physics
1 answer:
Dennis_Churaev [7]3 years ago
8 0

Answer:

Frequency of vibration will be equal to 720 Hz

Explanation:

It is given that car moves with a speed of 14.4 m/sec

Its mean that car cover 14.4 m in 1 sec

We have to find the frequency of vibration corresponding to this velocity

It is given that car has a tread pattern with a crevice every 2 cm

So number of crevices moved in 1 sec will be equal to =\frac{14.4}{0.02}=720

So frequency of these vibration will be equal to 720 Hz

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2. It is now 10:29 a.m., but when the bell rings at 10:30 a.m. Suzette will be late for French class for the third time this wee
Alex17521 [72]

Answer:

  • 62 seconds
  • no

Explanation:

The total travel time Suzette experiences is the sum of the times in each hallway. Using

  time = distance/speed

we can add the times.

  (35.0 m)/(3.50 m/s) +(48.0 m)/(1.20 m/s) +(60 m)/(5.0 m/s)

  = 10 s + 40 s + 12 s

  = 62 s

It takes Suzette 62 seconds to get to class. She does not beat the bell.

3 0
4 years ago
An astronaut on a small planet wishes to measure the local value of g by timing pulses traveling down a wire which has a large o
8_murik_8 [283]

Answer:

The gplanet is 0.193 m/s^2

Explanation:

The speed of the pulse is:

v=\frac{lengthofthewipe}{traveltime} =\frac{1.6}{0.0656} =15.24m/s

v=\sqrt{\frac{MgL}{m} } \\v^{2} =\frac{MgL}{m} \\g=\frac{mv^{2} }{ML}

where

m=mass of the wire=4 g= 4x10^-3 kg

M=mass of the object= 3 kg

Replacing values:

g=\frac{4x10^{-3}*15.24^{2}  }{3*1.6} =0.193 m/s^{2}

7 0
4 years ago
Compare the electric and gravitational force between the electron and the proton in a hydrogen atom. The electric charge of the
zepelin [54]

The gravitational attraction between electron and proton is 10−40 whereas electrostatic force of attraction between a proton and an electron is 10-8.

<h3>What is the gravitational force between electron and proton in a hydrogen atom?</h3>

The gravitational attraction between electron and proton in a hydrogen atom is weaker than the coulomb attraction by a factor of about 10−40 while on the other hand, the electrostatic force of attraction between a proton and an electron in a hydrogen atom is 10- 8 which is 9 times.

The electric charge of the electron and proton are the same i.e. -1.60x10-19C whereas their gravitational force is different due to difference in mass.

So we can conclude that gravitational attraction between electron and proton is 10−40 whereas electrostatic force of attraction between a proton and an electron is 10-8.

Learn more about force here: brainly.com/question/12970081

#SPJ1

7 0
2 years ago
If the velocity of the particle is uniform, then the path of the particle must be a​
lianna [129]

Answer:

write yoir question carefully i am not understanding it

6 0
4 years ago
The Pacific Giant Kelp grows at a rate of 18 in/day. How many centimeters per hour is this?
Airida [17]

For this case we must do a conversion. By definition we have to:

1 inch equals 2.54 centimeters

1 day equals 24 hours.

So, we have:18 \frac {in} {day} * \frac {1} {24} \frac {day} {h} * \frac {2.54} {1} \frac {cm} {in} =

Canceling units we have:

\frac {18 * 1 * 2.54} {24 * 1} \frac {cm} {h} =\\\frac {45.72} {24}\frac {cm} {h} =

1,905 \frac {cm} {h}

Answer:

1,905 \frac {cm} {h}

5 0
3 years ago
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