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svetlana [45]
4 years ago
8

Hydrobromic acid is added to a solution of lead(II) nitrate. Predict the products, and write a balanced equation for this reacti

on. Phases are not necessary.
Chemistry
1 answer:
Ber [7]4 years ago
7 0

Answer:

2HBr + Pb(NO₃)₂ → PbBr₂ + 2HNO₃

Explanation:

Hydrobromic acid (HBr), reacts with lead (II) nitrate (Pb(NO₃)₂) producing Lead(II) bromide (PbBr₂) and nitric acid (HNO₃). The reaction is:

HBr + Pb(NO₃)₂ → PbBr₂ + HNO₃

This reaction is unbalanced. You can see in products 2 Bromides but in reactants just 1. And in reactants 2 NO₃ but as product just 1. Thus, you can balance the equation, thus:

<em>2HBr + Pb(NO₃)₂ → PbBr₂ + 2HNO₃</em>

And this equation is the answer of your question!

<em />

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The molar enthalpy of vaporization of boron tribromide is 30.5 kj/mol, and its normal boiling point is 91°c. what is the vapor p
adell [148]
To answer this question, we will use the following equation:
<span>ln(P2/P1) = (∆Hvap/R)*((1/T1) - (1/T2)) 
</span>
Now we examine the givens of the problem and transform to standard units if required:
<span>∆Hvap = 30.5 kJ/mol 
</span>R is a constant = <span>8.314 x 10^-3 kJ K^-1 mol^-1 
T1 </span><span>= 91 celcius = 91 + 273= 364 Kelvin
</span>T2 = 20 celcius = 20 + 273 = 293 k3lvin
P1 is the standard atmospheric pressure = 760 mmHg
P2 is the value to be calculated

Substitute with these values in the equation:
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