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morpeh [17]
2 years ago
14

What are the complete Ionic and Net Ionic equations for the following

Chemistry
1 answer:
zhenek [66]2 years ago
5 0

Answer:

Check photo

Explanation:

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Non-metal ions are negative because...
abruzzese [7]

Explanation:

its b cz the gain electrons i think

6 0
3 years ago
A solution with [ OH] of 5 x 10-3 has a pH of
CaHeK987 [17]

Answer:

11·699

Explanation:

Given the concentration of hydroxide ion in the solution is 5 × 10^{-3} M

Assuming the temperature at which it is asked to find the pH of the solution be 298 K

<h3>At 298 K the dissociation constant of water is 10^{-14} </h3><h3>∴ pH + pOH = 14 at 298 K</h3><h3>pOH of the solution = -log( concentration of hydroxide ion )</h3>

∴ pOH of the given solution = - log(5 × 10^{-3} = -0·699 + 3 = 2·301

   pH of the given solution = 14 - 2·301 = 11·699

∴ pH of the solution = 11·699                                  

8 0
3 years ago
Calculate the freezing point of a solution that contains 8.0 g of sucrose (C12H22O11) in 100 g of H2O. Kf for H2O = 1.86C/m
Aleks04 [339]

The freezing point of the sucrose solution is -0.435°C.

<h3>What is the freezing point of the solution?</h3>

The freezing point of the solution is determined from the freezing point depression formula below:

  • ΔT = mKf(H₂O)

Kf(H₂O) = 1.86 Cm

m is molality of solution = moles of solute/mass of solvent

moles of sucrose = 8.0/342.3 = 0.0233 moles

m = 0.0233/0.1 = 0.233 molal

ΔT = 0.233 m * 1.86°C/m.

ΔT = 0.435 °C.

Freezing point of sucrose solution = 0°C - 0.435°C

Freezing point of sucrose solution  = -0.435°C.

In conclusion, the freezing point of sucrose solution is determined from the freezing point depression.

Learn more about freezing point depression at: brainly.com/question/19340523

#SPJ1

8 0
2 years ago
If two pretty beat friends exist would they actually be real or just 2 dogs<br>1.yes<br>2.no
12345 [234]

Answer:

I wouldn’t know I aint never seen two be pretty best friends

Explanation:

4 0
2 years ago
A sample of 450.0 g of water is found to contain 180 mg Cd. What is this concentration in parts per million?
navik [9.2K]

Answer:

The correct answer is 399.8 ppm

Explanation:

A concentration in parts per million (ppm) is equal to:

1 ppm = \frac{1 g solute}{10^{6}g solution}= \frac{1 mg solute}{1 kg solution}

Solute: Cd; Mass = 180 mg x (1 g/1000 mg) = 0.18 g

Solvent: Water ; Mass= 450.0 g x (1 kg/1000 g) = 0.45 kg

We have the following total mass of solution:

Mass of solution = Mass of solute + Mass of solvent = 0.18 g + 450 g = 450.18 g = 0.45018 kg

Finally, we divide the <u>mass of solute (in mg)</u> into the <u>mass of solution (in kg)</u> to obtain the ppm (in mg/Kg):

ppm = 180 mg/0.45018 kg = 399.8 mg/Kg = 399.8 ppm

4 0
3 years ago
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