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melisa1 [442]
4 years ago
9

water’s molar mass is 18.01 g/mol. The molar mass of glycerol is 92.09 g/mol. At 25 celsius, glycerol is more viscous than water

. which substance has the stronger intermolecular attraction
Chemistry
1 answer:
Gemiola [76]4 years ago
4 0

Answer is: glycerol because it is more viscous and has a larger molar mass.

Viscosity depends on intermolecular interactions.

The predominant intermolecular force in water and glycerol is hydrogen bonding.

Hydrogen bond is an electrostatic attraction between two polar groups in which one group has hydrogen atom (H) and another group has highly electronegative atom such as nitrogen (like in this molecule), oxygen (O) or fluorine (F).

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Answer:

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Explanation:

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What is the specific heat of a substance if 25 grams rises in temperature from 10 degrees Celsius to 25 degrees with the additio
Marina86 [1]

Answer:

0.75 cal/g°c

Explanation:

for specific heat we have formula:

Amount of heat absorbed or released = mass x specific heat of a substance x change in temperature.

ΔQ=m x c x ΔT

where c= specific heat

m= mass of a substance

ΔT = total temperature

ΔQ = Amount of heat

so for specific heat,

c= ΔQ/mxΔT

c= 280/25x (25-10)

c= 280/375

c= 0.75 cal/g°c

4 0
4 years ago
Write a reaction to describe the behavior of the following substances in water. please include all phases.
lorasvet [3.4K]

3NF3 + 5H2O → HNO3 + 2NO + 9HF

Nitrogen fluoride reacts with water to produce nitric acid, nitric oxide, and hydrogen fluoride. The reaction slowly takes place in a boiling solution.

CH2CH2 + H2O → CH3CH2OH

Ethylene is a hydrocarbon with water that creates ethanol and ethanol is an alcohol

4 0
3 years ago
Calculate the enthalpy of the reaction
harkovskaia [24]

Answer : The enthalpy of the reaction is, -2552 kJ/mole

Explanation :

According to Hess’s law of constant heat summation, the heat absorbed or evolved in a given chemical equation is the same whether the process occurs in one step or several steps.

According to this law, the chemical equation can be treated as ordinary algebraic expression and can be added or subtracted to yield the required equation. That means the enthalpy change of the overall reaction is the sum of the enthalpy changes of the intermediate reactions.

The given enthalpy of reaction is,

4B(s)+3O_2(g)\rightarrow 2B_2O_3(s)    \Delta H=?

The intermediate balanced chemical reactions are:

(1) B_2O_3(s)+3H_2O(g)\rightarrow 3O_2(g)+B_2H_6(g)     \Delta H_A=+2035kJ

(2) 2B(s)+3H_2(g)\rightarrow B_2H_6(g)    \Delta H_B=+36kJ

(3) H_2(g)+\frac{1}{2}O_2(g)\rightarrow H_2O(l)    \Delta H_C=-285kJ

(4) H_2O(l)\rightarrow H_2O(g)    \Delta H_D=+44kJ

Now we have to revere the reactions 1 and multiple by 2, revere the reactions 3, 4 and multiple by 2 and multiply the reaction 2 by 2 and then adding all the equations, we get :

(when we are reversing the reaction then the sign of the enthalpy change will be change.)

The expression for enthalpy of the reaction will be,

\Delta H=-2\times \Delta H_A+2\times \Delta H_B-6\times \Delta H_C-6\times \Delta H_D

\Delta H=-2(+2035kJ)+2(+36kJ)-6(-285kJ)-6(+44)

\Delta H=-2552kJ

Therefore, the enthalpy of the reaction is, -2552 kJ/mole

4 0
3 years ago
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