Answer : The amount of codeine in one teaspoonful is, 30 mg
Explanation : Given,
Amount of codeine per fluid ounce = 60 mg
Now we have to determine the amount of codeine present in one teaspoonful.
As we know that:
1 teaspoonful = 0.5 fluid ounce
As, the amount of codeine per fluid ounce = 60 mg
So, the amount of codeine 0.5 fluid ounce =
Thus, the amount of codeine in one teaspoonful is, 30 mg
The density of liquid water is 1 kg/L.
Mass of water = (1 kg/L)(2.5 L)(1000 g/1 kg) = 2500 g water
The molar mass of water is 18 g/mol.
Moles of water = 2500 g / 18 g/mol = 138.889 mol water
According to Avogadro's number, in one mole of any substance, there are 6.022×10²³ atoms.
Atoms of water = 138.889 mol * 6.022×10²³ atoms/mol = 8.364×10²⁵ atoms of water
In every atom of water, there are 10 protons: 8 from one oxygen atom, and 1 each from the two hydrogen atoms.
Protons of water = 8.364×10²⁵ atoms * 10 protons/atom
<em>Protons of water = 8.364×10²⁶ </em>
Nucleus:direct all the organelles
Answer:
The concentration of the resulting solution is 0.25 or one quarter of the standard solution
Explanation:
Whereby the molar concentration of the standard solution is P molar per liter, we have
25 ml of the standard solution contains
25/1000×P moles of the standard solution such that the resultant solution has a volume of 25 + 75 = 100 ml contains 0.025 P moles of the standard solution
The concentration of a solution is the number of moles contained per liter, which gives
100 ml contains 0.025 P moles
1 liter = 1000 ml will contain 1000/100 × 0.025 = 0.25 P moles of the stanard solution
Therefore, the concentration of the resulting solution is 0.25 or one quarter of the standard solution.