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kap26 [50]
3 years ago
9

Kobe adds 60 grams of the salt NH4Cl to 100 mL of water at 70°C. He then adds 20 grams more to the water without changing the te

mperature. What will happen to the added 20 grams?
Chemistry
1 answer:
poizon [28]3 years ago
6 0

Answer:

rip kobe

Explanation:

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3 years ago
A volume of 125 mL of H2O is initially at room temperature (22.00 ∘C). A chilled steel rod at 2.00 ∘C is placed in the water. If
VMariaS [17]

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41.9 g

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Q = c × m × ΔT

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ΔT: change in temperature

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According to the law of conservation of energy, the sum of the heat released by the water (Qw) and the heat absorbed by the steel (Qs) is zero.

Qw + Qs = 0

Qw = -Qs

cw × mw × ΔTw = -cs × ms × ΔTs

(4.18 J/g.°C) × 125 g × (21.30°C-22.00°C) = -(0.452J/g.°C) × ms × (21.30°C-2.00°C)

ms = 41.9 g

3 0
3 years ago
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