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STALIN [3.7K]
3 years ago
14

Conclusions drawn from personal beliefs are

Chemistry
2 answers:
Lady bird [3.3K]3 years ago
7 0
The term for a conclusion drawn strictly from personal belief is "opinion."<span> Synonyms for the word "opinion" include: "point of view," "judgement," and "assessment."</span>
kobusy [5.1K]3 years ago
5 0
The answer is subjective
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Bromine, a liquid at room temperature, has a boiling point of 58°C and a melting point of –7.2°C. Bromine can be classified as a
andreev551 [17]

Answer:

Pure substance.

Explanation:

7 0
3 years ago
Calculate the amount of solvent needed to prepare 50g of 10% solution of Tincture iodine. Name the solvent.
sergeinik [125]

Answer:

Calculate the amount of solvent needed to prepare 50g of 10% solution of tincture Iodine.

Name the solvent

Explanation:

sodium

Hope it is helpful.....

7 0
3 years ago
I need help with like 35 questions anyone willing to help please let me know I have discord
posledela

Answer and Explanation:

The molar mass of a substance is all of the weights from the elements combined.

So, we have the elements

CU, S, and O_{4}

CU has a mass is 65

S mass is 32

O has a mass of 16, but there's 4 atoms of O, so we do 16 times 4, which is 64.

Now we add.

65 + 32 + 64 is 161.

<u>So, the answer is 160, or answer choice A.</u>

<em><u>#teamtrees #PAW (Plant And Water)</u></em>

3 0
3 years ago
The aromatic hydrocarbon cymene (C10H14) is found in nearly 100 spices and fragrances, including coriander, anise, and thyme. Th
andrezito [222]

Answer : The thermal energy produced during the complete combustion of one mole of cymene is -7193 kJ/mole

Explanation :

First we have to calculate the heat released by the combustion.

q=c\times \Delta T

where,

q = heat released = ?

c = specific heat of calorimeter = 3.640kJ/^oC

\Delta T = change in temperature = 19.35^oC

Now put all the given values in the above formula, we get:

q=3.640kJ/^oC\times (19.35)^oC

q=70.43kJ

Thus, the heat released by the combustion = 70.43 kJ

Now we have to calculate the molar enthalpy combustion.

\Delta H=-\frac{q}{n}

where,

\Delta H = molar enthalpy combustion = ?

q = heat released = 70.43 kJ

n = number of moles cymene = \frac{\text{Mass of cymene}}{\text{Molar mass of cymene}}=\frac{1.608g}{164.22g/mol}=0.009792mole

\Delta H=-\frac{70.43kJ}{0.009792mole}=-7193kJ/mole

Therefore, the thermal energy produced during the complete combustion of one mole of cymene is -7193 kJ/mole

4 0
3 years ago
Molar mass of lead(ll)chloride
Fiesta28 [93]
I look for your answer 278.1 g/mol I hope this help
5 0
3 years ago
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