Al2(SO4)3 would be the formula.
Answer:
56972.17K
Explanation:
P = 4.06kPa = 4.06×10³Pa
V = 14L
n = 0.12 moles
R = 8.314J/Mol.K
T = ?
We need ideal gas equation to solve this question
From ideal gas equation,
PV = nRT
P = pressure of the ideal gas
V = volume the gas occupies
n = number of moles
R = ideal gas constant
T = temperature of the gas
PV = nRT
T = PV / nR
T = (4.06×10³ × 14) / (0.12 × 8.314)
T = 56840 / 0.99768
T = 56972.17K
Note : we have a large number for temperature because we converted the value of pressure from kPa to Pa
The density of the unknown material is 0.213 ml/g
<h3>
Apparent density of the unknown material</h3>
The apparent density of the unknown material is calculated as follows;
Volume of the unknown substance = 126 ml - 102 ml = 24 ml
Density of the unknown substance = mass/volume
Density of the unknown substance = 24 ml / 112.6 g
Density of the unknown substance = 0.213 ml/g
Thus, the density of the unknown material is 0.213 ml/g
Learn more about density here; brainly.com/question/6838128
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<em>The number of protons and electrons in a neutral atom of the element are;</em>
D. 29 protons and 29 electrons
<u>The atomic number of an element is equal to the number of protons in the nucleus of each atom of that element.</u>
<u>Thus copper has an atomic number of 29, all atoms of copper will have 29 protons.</u>
Answer:
The number of sulfur atoms in 1 g of sulfur is:- 
atoms
Explanation:
Avogadro’s number represent the number of the constituent particles which are present in one mole of the substance. It is named after scientist Amedeo Avogadro and is denoted by 
.
Avogadro constant:-
Given atomic mass of sulfur = 32 u
Which means that:-
32 g of sulfur contains 
of atoms
Also,
1 g of sulfur contains 
of atoms
<u>So, The number of sulfur atoms in 1 g of sulfur is:- atoms</u>
