Answer:
Step-by-step explanation:
I think your question missed key information, allow me to add in and hope it will fit the orginal one
<em>For the graph below, what should the domain be so that the function is at least 200? graph of y equals minus 2 times the square of x plus 30 times x plus 200
</em>
My answer:
Given the above information, we have:
To make the function is at least 200, it means that:
≥ 200
<=> 
≥ 0
<=> x(-2x+30) ≥ 0
This is the product of two numbers hence would be positive only if either both are positive or both are negative
x ≥ 0 and (-2x+30) ≥ 0
<=> 0 ≤ x ≤ 15
Then we get
This is inconsistent as a value cannot be less than 0 and greater than 15
=> our correct answer is
Hope it will find you well.
Answer:
5
Step-by-step explanation:
Answer:
The answer would be x=4.
Step-by-step explanation: Step 1: Simplify both sides of the equation.
2x+3(5x−7)=47
2x+(3)(5x)+(3)(−7)=47(Distribute)
2x+15x+−21=47
(2x+15x)+(−21)=47(Combine Like Terms)
17x+−21=47
17x−21=47
Step 2: Add 21 to both sides.
17x−21+21=47+21
17x=68
Step 3: Divide both sides by 17.
17x/17=68
17x=68
x=4
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➷ The correct number sentence is D. 5.5 + (-2.5) = 3.0
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Answer: range= 26, variance= 80 and standard deviation= 8.94
Step-by-step explanation:
Range = highest - lowest
Range = 146 - 120
Range= 26
Let m be mean
M=mean=sum/n
Mean=(120+134+146+127+138+133) / 6
M=798/6
M=133
The standard deviation sample formula:
S.D = sqrt( Summation of |x-m|^2 / n-1)
Let start finding:
|x-m|^2
For 1st: |120-133|^2=169
For 2nd: |134-133|^2=1
For 3rd: |146-133|^2=169
For 4th: |127-133|^2=36
For 5th: |138-133|^2=25
For 6th: |133-133|^2=0
Summation of |x-m|^2 = 400
The standard deviation formula is :
S.D = sqrt( Summation of |x-m|^2 / n-1)
S.D= sqrt(400 / 5)
S.D=sqrt(80)
S.D= 8.94
Variance = (Summation of |x-m|^2 / n-1)
Variance= 400/5
Variance= 80
