Answer:
Explanation:
acceleration is the time rate of change of velocity
a = (51 - 20) / 3 = 10⅓ mi/hr/s
which should probably be converted to standard units.
10⅓ mi/hr/s(5280 ft/mi) / 3600 s/hr) = 15.15555... ≈ 15.2 ft/s²
which is roughly half the acceleration of gravity.
Answer:
a) p₀ = 1.2 kg m / s, b) p_f = 1.2 kg m / s, c) θ = 12.36, d) v_{2f} = 1.278 m/s
Explanation:
For this exercise we define a system formed by the two balls, which are isolated and the forces during the collision are internal, therefore the moment is conserved
a) the initial impulse is
p₀ = m v₁₀ + 0
p₀ = 0.6 2
p₀ = 1.2 kg m / s
b) as the system is isolated, the moment is conserved so
p_f = 1.2 kg m / s
we define a reference system where the x-axis coincides with the initial movement of the cue ball
we write the final moment for each axis
X axis
p₀ₓ = 1.2 kg m / s
p_{fx} = m v1f cos 20 + m v2f cos θ
p₀ = p_f
1.2 = 0.6 (-0.8) cos 20+ 0.6 v_{2f} cos θ
1.2482 = v_{2f} cos θ
Y axis
p_{oy} = 0
p_{fy} = m v_{1f} sin 20 + m v_{2f} cos θ
0 = 0.6 (-0.8) sin 20 + 0.6 v_{2f} sin θ
0.2736 = v_{2f} sin θ
we write our system of equations
0.2736 = v_{2f} sin θ
1.2482 = v_{2f} cos θ
divide to solve
0.219 = tan θ
θ = tan⁻¹ 0.21919
θ = 12.36
let's look for speed
0.2736 = v_{2f} sin θ
v_{2f} = 0.2736 / sin 12.36
v_{2f} = 1.278 m / s
Answer:
45.09 m/s^2
Explanation:
from the question we were given the following parameters
mass = 931.9 kg
initial velocity (V1) = 0 m/s ( since it started from rest )
final velocity (V2) = 25.7 m/s
time (t) = 0.57 s
The average acceleration is given by:
a = ( V2 - V1 ) / t
therefore
a = (25.7 - 0) / 0.57 = 45.09 m/s^2
Answer:
Explanation:
A scientist collects a core sample from 60 km deep in Earth. Which characteristic will she most likely observe in this sample? C. The sample mainly consists of ...
Answer: b) Technician B only
Explanation:
For the fact no break fluid flows out Of the bleeder valve when It’s opened, that means there’s a blockage stopping the fluid from flowing off.
