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Ilya [14]
2 years ago
14

1. What is the difference between the two divisions of the skeletal system?

Physics
1 answer:
laiz [17]2 years ago
8 0

Answer:

Explanation:

wdym

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where would information on the chemical and physical properties of a specific chemical be located in a laboratory or in the work
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Answer:

Both

Explanation:

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ASK YOUR TEACHER A baseball with a mass of 146 g is thrown horizontally with a speed of 40.6 m/s (91 mi/h) at a bat. The ball is
RideAnS [48]

Answer:

Explanation:

mass of the ball = 146 g = 146 / 1000 = 0.146 kg

initial speed of the ball = 40.6 m/s

final speed of the ball = - 45.1 m/s

time of impact = 1.05 ms = 1.05 / 1000 = 0.00105 s

impulse, Ft = change in momentum = mv - mu = m (v-u)

F = m (v - u) / t = 0.146 kg ( -45.1 -40.6) / 0.00105 s = -11916.4 N

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3 years ago
The thermal energy in a heat engine is used to move a piston. Which best describes why this is possible?
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The increase in entropy is directly related to the increase in temperature.
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3 years ago
You throw a ball vertically upward so that it leaves the ground with velocity +5.00 m/s. (a) What is its velocity when it reache
saw5 [17]

Answer:

(a) The velocity (v)  of the ball when reaches its maximum altitude is zero .

     v= 0

(b) The acceleration of an object free fall motion is constant and is equal to the acceleration due to gravity,then, At maximum height the acceleration of ball  is  g =-9,8 m/s².

(c)velocity of the ball when it returns to the ground :

v_{f} =5 \frac{m}{s} in direction -y

v_{f} =-5 \frac{m}{s}

(d)a=g = -9,8 m/s² : acceleration of the ball when it returns to the ground

Explanation:

Ball Kinematics

We apply the free fall formula:

vf²=v₀²+2*a*y Formula (1)

y:displacement in meters (m)  

v₀: initial speed in m/s  

vf: final speed in m/s  

a: acceleration

Data

v₀ = +5.00 m/s

Problem development

(a) What is its velocity when it reaches its maximum altitude?

in ymax,  vf=0 , At maximum height the velocity is zero and the ball falls freely

(b) What is its acceleration at this point?

The acceleration of an object free fall motion is constant and is equal to the acceleration due to gravity,then, At maximum height the acceleration of ball  is 9,8 m/s².

g= -9.8 m/s²

c) What is the velocity with which it returns to ground level?

We apply the Formula (1) to calculate the maximum height (h):

Ball movement up

vf²=v₀²+2*a*h

0 = (5)² +2*(-9.8)*h

19.6*h = 25

h= 25/19.6 = 1.275 m

Ball movement down

The distance the ball goes up is equal to the distance it goes down

h= 1.275 m , v₀=0

vf²=v₀²+2*a*h

vf²=0+2*(-9.8)*(-1.275)  

v_{f} = \sqrt{25}

v_{f} =5 \frac{m}{s} in direction -y

v_{f} =-5 \frac{m}{s}

(d) What is its acceleration at this point?

a is constant , a= g = -9.8 m/s²

7 0
3 years ago
Read 2 more answers
When an object is in motion due to only the force of gravity?
Genrish500 [490]
When it falls though a vaccum,it is subjected to only one external force,the gravitational force.
7 0
3 years ago
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