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Serga [27]
3 years ago
5

Which contains the greatest mass of oxygen: 0.75 moles of ethanol ( C2H5OH ), 0.60 mole of formic acid ( HCO2H ), or 1.0 mole of

water ( H2O )? Why?
Chemistry
2 answers:
Luda [366]3 years ago
7 0

Answer:

In conclussion, 0.60 moles of HCOOH contains the greatest mass of O

Explanation:

Let's make some rules of three, to solve this problem:

1 mol of ethanol has 2 moles of C, 6 moles of H, and 1 mol of oxygen

Therefore, 0.75 moles of ethanol must have 0.75 mol of oyxgen

Let's convert the moles to mass → 0.75 mol . 16 g/ 1 mol = 12 g

1 mol of formic acid has 2 moles of H, 1 mol of C and 2 mol of oxygen

0.60 moles of formic acid must have  (0.6 .2) / 1 = 1.2 mol of O

If we convert the amount to mass → 1.2 mol . 16 g/ 1mol = 19.2 g

1 mol of water has 1 mol of oyxgen

Therefore, we have 1 mol of oxygen with a mass of 16 g.

In conclussion, 0.60 moles of HCOOH contains the greatest mass of O

TiliK225 [7]3 years ago
6 0

Answer:

0.60 mole of formic acid contains the greatest mass of oxygen

(19.2 grams)

Explanation:

Step 1: Data given

Moles of ethanol = 0.75 moles

Molar mass ethanol = 46.07 g/mol

Moles of formic acid = 0.60 moles

Molar mass of formic acid = 46.03 g/mol

Moles of H2O = 1.0

Molar mass of H2O = 18.02 g/mol

Step 2: Calculate moles of oxygen in each

Ethanol: For 1 mol ethanol we have 1 mol oxygen

For 0.75 moles ethanol we have 0.75 moles O

Mass O = 0.75 moles * 16.0 g/mol = 12.0 grams O

Formic acid: For 1 mol formic acid, we have 2 moles O

For 0.60 moles formic acid, we have 2*0.60 = 1.20 moles O

Mass O = 1.20 moles * 16.0 g/mol = 19.2 grams O

H2O: for 1.0 mol H2O we have 1 mol O

Mass O = 18.02 g/mol * 1.0 mol = 18.02 grams

0.60 mole of formic acid contains the greatest mass of oxygen

(19.2 grams)

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This doesn't need an ICE chart. Both will fully dissociate in water.

Assume HClO4 and KOH reacts with one another. All you need to do is determine how much HClO4 will remain after the reaction. Calculate pH.

Step 1:

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HClO4+KOH ⇔ KClO4 + H2O

the ratio of HClO4 to KOH is going to be 1:1. Each mole of KOH we add will fully react with 1 mole of HClO4

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Remember:

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Since both reactants fully dissociate and are used in a 1:1 ratio, we just subtract the number of moles of KOH from the number of moles of HClO4:

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