The heat required to vaporize 43.9 g of acetone at its boiling point is calculated as below
the heat of vaporization of acetone at its boiling point is 29.1 kj/mole
find the moles of acetone = mass/molar mass
= 43.9g /58 g/mol =0.757 moles
heat (Q) = moles x heat of vaporization
= 29.1 kj/mole x 0.757 moles = 22.03 kj
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An oxygen gas is a diatomic molecule which means that each molecule is composed of 2 atoms. Its symbol is O2.
Each oxygen atom has a molar mass of 16 g/mol. The molar mass of oxygen gas is calculated below,
molar mass = 2 x (16 g/mol) = 32 g/mol
To determine the number of moles in 52.5 grams of oxygen, divide the given mass by the calculated molar mass.
n = 52.5 grams / (32 gram/ mol)
n = 1.64 moles
Thus, there are 1.64 moles of oxygen gas.
Increase in heat, molecules start to escape and it turns to vapor
Answer:
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