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Ksivusya [100]
3 years ago
11

Friction is just hot air rubbing off on the inevitable force of solidprove me wrong

Physics
2 answers:
algol133 years ago
8 0

Answer:

lol ur not wrong

Explanation:

IrinaVladis [17]3 years ago
4 0
I can’t prove you working ur too good
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The blackbody curved for a star named Beta is shown below. What is the surface temperature of the star rounded to the nearest wh
marshall27 [118]
<span>Then, since the peak wavelength of the star Beta is 200nm, use Wein law and round 200 to the nearest WHOLE NUMBER. Hope that helps. </span>
3 0
3 years ago
Read 2 more answers
Io, a satellite of Jupiter, is the most volcanically active moon or planet in the solar system. It has volcanoes that send plume
Mamont248 [21]

Answer:

1331.84 m/s

Explanation:

t = Time taken

u = Initial velocity

v = Final velocity = 0

s = Displacement = 490 km

a = Acceleration

g = Acceleration due to gravity = 1.81 m/s² = a

From equation of linear motion

v^2-u^2=2as\\\Rightarrow -u^2=2as-v^2\\\Rightarrow u=\sqrt{v^2-2as}\\\Rightarrow u=\sqrt{0^2-2\times -1.81\times 490000}\\\Rightarrow u=1331.84\ m/s

The speed of the material must be 1331.84 m/s in order to reach the height of 490 km

3 0
3 years ago
Read 2 more answers
Calculate the energy of the green light emitted, per photon, by a mercury lamp with a frequency of 5.49 × 1014 hz. calculate the
olga nikolaevna [1]
The energy of a single photon is given by:
E=hf
where
E is the energy
h is the Planck constant
f is the frequency of the light

The light in our problem has a frequency f=5.49 \cdot 10^{14}Hz, so the energy of each photon of that light is:
E=hf=(6.6 \cdot 10^{-34} Js)(5.49 \cdot 10^{14} Hz)=3.64 \cdot 10^{-19} J
5 0
3 years ago
If a 100-n net force acts upon a 50g car, what will the acceleration of the car be
Brrunno [24]

Answer:

2m/s

Explanation:

The formula for acceleration can be found by [ a = f/m ]

We are given the force [ 100N ] and the mass [ 50g ].

We can use these values to solve for the acceleration.

a = 100/50

a = 2m/s

Best of Luck!

3 0
3 years ago
Electrons and protons travel from the Sun to the Earth at a typical velocity of 3.83 ✕ 105 m/s in the positive x-direction. Thou
Leona [35]

Answer:

F=2.84*10^{-26}N  & -y direction

F=2.84*10^{-26}N & +y direction

Explanation:

From the question we are told that:

Speed of electron V_e=3.83 * 10^5 m/s +x direction

Earths magnetic field B_e=3.04 * 10^-^8 +z direction

a)

Generally the equation for magnetic force F_m is mathematically given by

F=q(V_e*B_e)

where

q=1.6*10^{-19}c\\\=i*\=z=-\=j

F=1.6*10^{-19}(3.83 * 10^5 m/s*3.04 * 10^-^8)

F=1.6*10^{-19}(3.83 * 10^5 m/s*3.04 * 10^-^8)

F=-2.84*10^{-26}N \=j

Magnitude & Direction

F=2.84*10^{-26}N  -y direction

b)

Generally the equation for magnitude and direction of the magnetic force on an electron. is mathematically given by

\=F'=-1.6*10^{-19}(3.83 * 10^5 m/s*3.04 * 10^-^8)

\=F'=-2.84*10^{-26}N \=j

Magnitude & Direction

F=2.84*10^{-26}N & +y direction

5 0
3 years ago
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