Answer: 7.90 g/cm^3
Explanation:
Density = Mass / Volume
The first step is to find the volume by multiplying the three measures of the cube that have been provided.
3.50 x 0.755 x 2.25 = 5.95 cm^3
Now we can plug the numbers into our equation.
Density = 47.0g / 5.95 cm^3
Density = 7.90 g/cm^3
There are 2.32 x 10^6 kg sulfuric acid in the rainfall.
Solution:
We can find the volume of the solution by the product of 1.00 in and 1800 miles2:
1800 miles2 * 2.59e+6 sq m / 1 sq mi = 4.662 x 10^9 sq m
1.00 in * 1 m / 39.3701 in = 0.0254 m
Volume = 4.662 x 10^9 m^2 * 0.0254 m
= 1.184 x 10^8 m^3 * 1000 L / 1 m3
= 1.184 x 10^11 Liters
We get the molarity of H2SO4 from the concentration of [H+] given by pH = 3.70:
[H+] = 10^-pH = 10^-3.7 = 0.000200 M
[H2SO4] = 0.000100 M
By multiplying the molarity of sulfuric acid by the volume of the solution, we can get the number of moles of sulfuric acid:
1.184 x 10^11 L * 0.000100 mol/L H2SO4 = 2.36 x 10^7 moles H2SO4
We can now calculate for the mass of sulfuric acid in the rainfall:
mass of H2SO4 = 2.36 x 10^7 moles * 98.079 g/mol
= 2.32 x 10^9 g * 1 kg / 1000 g
= 2.32 x 10^6 kg H2SO4
Molar mass H₂SO₄ = 98.079 g/mol
1 mol -------- 98.079 g
? mole ------ 0.0960 g
moles = 0.0960 * 1 / 98.079
= 0.0960 / 98.079
= 9.788 x 10⁻⁴ moles
hope this helps!
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