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True [87]
3 years ago
9

A 1.547 g sample of blue copper(II) sulfate pentahydrate, ‍ , is heated carefully to drive off the water. The white crystals of

that are left behind have a mass of g. How many moles of ‍ were in the original sample? Show that the relative molar amounts of and ‍ agree with the formula of the hydrate.
Chemistry
1 answer:
sweet [91]3 years ago
8 0

Answer:

=6.2x10^{-3}mol CuSO_4

Explanation:

Hello,

By developing the following stoichiometric relationship, the required amount could be found as follows:

- Moles of CuSO_4:

1.547gCuSO_4.5H_2O *\frac{1molCuSO_4.5H_2O}{249.5gCuSO_4.5H_2O} *\frac{1mol CuSO_4}{1mol CuSO_4.5H_2O} =6.2x10^{-3}mol CuSO_4

- Grams of CuSO_4

1.547gCuSO_4.5H_2O *\frac{1molCuSO_4.5H_2O}{249.5gCuSO_4.5H_2O} *\frac{1mol CuSO_4}{1mol CuSO_4.5H_2O}*\frac{159.5g CuSO_4}{1mol CuSO_4} =0.989 g CuSO_4

- Moles of water:

1.547gCuSO_4.5H_2O *\frac{1molCuSO_4.5H_2O}{249.5gCuSO_4.5H_2O} *\frac{5mol H_2O}{1mol CuSO_4.5H_2O}=0.031mol H_2O

Finally, one could see that the mass of the anhydrous compound is less than the pentahydrated compound since it is waterless.

Best regards.

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