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Olin [163]
3 years ago
15

Explain how to identify a conjugate acid and a conjugate base in an acid base reaction.

Chemistry
1 answer:
alekssr [168]3 years ago
7 0

Answer:

- Identify the acid and base in the reaction.

- What is left of the base after the reaction is known as the conjugate acid, while what is left of the acid after the reaction is known as the conjugate base.

Explanation:

<u>Types of acids and bases</u><u>:</u>

When we are looking at conjugate acid and base, the type of acid and base we should focus on are Brønstead acid and base.

Brønsted acid: proton donor

Brønsted base: proton acceptor

Do note that proton here refers to hydrogen ion, H⁺.

Other types of acids and bases includes arrhenius acid/base and Lewis acid/base.

<u>Definition</u><u>:</u>

Conjugate acid is what remains of the acid when a Brønsted acid donates a proton, while conjugate base is the newly formed protonated species when a Brønsted base accepts a proton.

<u>Example</u><u>:</u>

Let's look at an example of a Brønsted acid-base reaction:

NH₃(aq) +H₂O(l) ⇌ NH₄⁺(aq) +OH⁻(aq)

Here, the base is NH₃ and the acid is H₂O.

NH₄⁺ is the conjugate acid, while OH⁻ is the conjugate base.

<u>Note</u><u>:</u>

For a Brønsted acid- base reaction, whether a substance behaves as an acid or a base depends on what it is reacting with. Although H₂O behaves as an acid in this example, it behaves as a base when reacting with HCl.

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How many atoms are in 2.45 moles of hydrogen
allochka39001 [22]

Answer:

There are 1.4754246675000002e+24 atoms of Hydrogen within the measurement of 2.45 moles of hydrogen!

Explanation:

6 0
3 years ago
The number of ions in 17.1 gm of aluminum sulphate Al2 (SO4)3 =….. [Molar mass of Al2 (SO4)3 = 342 gm]
katen-ka-za [31]

Answer:

1.51 X 10^23 ions

Explanation:

The number of ions in 17.1 gm of aluminum sulphate Al2 (SO4)3 =….. [Molar mass of Al2 (SO4)3 = 342 gm]

in one molecule of Al2(SO4)3 there are 5 ions 2 aluminum and 3 sulfate ions

in 2 molecules there are 2X5= 10 ions

in 10 molecules there are 10X5 = 50 ions

molar mass of Al2(SO4)3 = (2 X 26.98) +( 3 X 32.1) + (3 X 4 X 16.0 ) =342.gms = 17.1/342 =0.0500 moles

1  mole =6.02 X 10^23 molecules ( see Avogadros number)

0.0500 moles = 0.0500 X 6.02 X 10^23 molecules =

0.301 X 10^23 molecules = 3.01 X 10^22 molecules

We determined that each molecule of Al2(SO4)3 has 5 ions

so 3.01 X10^22 molecules have 5 X 3.01 X 10^22 ions =

15.05 X 10^22 ions = 1.51 X 10^23 ions

3 0
3 years ago
Convert 213.62 grams of xenon gas at STP to L.
jolli1 [7]

Answer: The coefficient is 3.645

The exponent is 1

There are 4 significant digits

The rightmost significant figure is 5

Explanation:

Scientific notation is defined as the representation of expressing the numbers that are too big or too small and are represented in the decimal form with one digit before the decimal point times 10 raise to the power.

For example : 5000 is written as 5.0\times 10^3

According to avogadro's law, 1 mole of every gas contains avogadro's number 6.023\times 10^{23} of particles, occupy 22.4 L at STP and weighs equal to its molecular mass.

131.29 g of Xe occupy = 22.4 L at STP.

Thus 213.62 g of Xe occupy = \frac{22.4}{131.29}\times 213.62=36.45L at STP.

Scientific notation = 3.645\times 10^1L

The coefficient is 3.645

The exponent is 1

There are 4 significant digits

The rightmost significant figure is 5

4 0
3 years ago
which method would be best for separating the compounds of a mixture that is made from two diffrent liquids
kobusy [5.1K]

Answer:

fractional distillation since ot depends on the different liquids to have different boiling points

5 0
2 years ago
hat is the percentage of water in the following compound? Answer using three significant figures. Sodium carbonate decahydrate,
BigorU [14]
You need to find the whole molar mass of the compound using the periodic table to add the values. 

Na2CO3= (2 x 23.0) + 12.0 + (3 x 16.0)= 106 g/mol
H2O= 10 x [ (2 x 1.01 ) + (16.0) ]= 180.2 g/mol

the total molar mass is 106 + 180.2 = 286.2 g/mol

the percentage of water you can find by doing "parts over the whole"

H2O%= 180.2 / 286.2 X 100= 63.0%
7 0
3 years ago
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