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Natalka [10]
3 years ago
13

The severity of a tropical storm is related to the depressed atmospheric pressure at its center. In August 1985, Typhoon Odessa

in the Pacific Ocean featured maximum winds of about 90 mi/hr and pressure that was 40.0 mbar lower at the center than normal atmospheric pressure. In contrast, the central pressure of Hurricane Andrew (pictured) was 90.0 mbar lower than its surroundings when it hit south Florida with winds as high as 165 mi/hr. If a small weather balloon with a volume of 4.0 L at a pressure of 1.00 atmospheres was deployed at the edge of Typhoon odessa what was the volume of the balloon when it reached the center?
Physics
1 answer:
xxMikexx [17]3 years ago
7 0

Answer:

4.16 L

Explanation:

Assuming constant temperature,

At the edge of Typhoon Odessa: P₁ = 1 atm = 1013.3 mbar,

V₁  = 4.0 L

At the center of Typhoon Odessa: P₂ = (1013.3 - 40.0) mbar = 973.3 mbar

V₂ = ? L

For a fixed amount of gas at constant temperature (Boyle's law) : P₁V₁ = P₂V₂

V₂ = V₁ × (P₁/P₂)

V₂= (4.0) × (1013.3/973.3)

V₂= 4.16 L

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Explanation:

Given

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Moment of inertia, I = 0.5 kgm²

The rotational kinetic energy, KE(rot) of an object is given by

KE(rot) = 1/2Iw²

Also, the angular velocity is given

w = v/r

Firstly, we calculate the angular velocity. Since it's needed in calculating the Kinetic Energy

w = v/r

w = 17.1 / 0.47

w = 36.38 rad/s

Now, substituting the value of w, with the already given value of I in the equation, we have

KE(rot) = 1/2Iw²

KE(rot) = 1/2 * 0.5 * 36.38²

KE(rot) = 0.25 * 1323.5

KE(rot) = 330.88 J

6 0
3 years ago
Two bodies of masses 1000kg and 2000kg are separated 1km which is the gravitational force between them
denpristay [2]

Answer:

1.33×10⁻¹⁰ N

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F = GMm / r²

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What is the net force of a 25 g object with an acceleration of 3 m/s^2? 100PTS
gayaneshka [121]

Explanation:

Force=Mass×acceleration

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force=75N

5 0
3 years ago
Read 2 more answers
How is the density of a substance calculated?
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1).  Take a sample of the substance.  The sample should be the largest
possible that will allow it to be be easily handled and the following steps
to be performed with it. 
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can improve the accuracy of the measurements you make, and therefore
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3 0
3 years ago
Imagine a system where a block rests on an inclined plane. The block is then given an initial push so that it starts sliding dow
katen-ka-za [31]

Answer:

the correct affirmation is the 3

Explanation:

Let's analyze the problem with Newton's second law before looking at the claims.

X axis parallel to the plane, positive down

      F -fr + Wₓ = ma

Y Axis perpendicular to the plane

      N -Wy = 0

With trigonometry

     Wₓ = W sin θ

     Wy = w cos θ

Let's multiply by the displacement along the plane, to relate to the work, which has as expression W = F d

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Push                  W₁ = Fd

frictional force  W₂ = -fr d

gravity               W₃ = Wx d

    W₁ + W₃ -W₂ = m a d

Analysis affirmations:

R1) false. The work of gravity is the subtraction    

R2) false. Each force contributes according to its magnitude

R3) true. In the equation we see that, if the acceleration is zero, W2 = W1 + W3

R4) False. It equals the difference

the correct affirmation is the 3

6 0
3 years ago
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