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Illusion [34]
3 years ago
7

Suppose a car of mass m is moving at a constant speed v of

Physics
1 answer:
SIZIF [17.4K]3 years ago
4 0

Answer:

The angle of banked curve that makes the reliance on friction unnecessary is

\arcsin(v^2/(gR))

Explanation:

In order the car to stay on the curve without friction, the net force in the direction of radius should be equal or smaller than the centripetal force. Otherwise the car could slide off the curve.

The only force in the direction of radius is the sine component of the weight of the car

w_r = mg\sin(\theta)

The cosine component is equivalent to the normal force, which we will not be using since friction is unnecessary.

Newton’s Second Law states that

F_{net} = ma = mg\sin(\theta)\\\sin(\theta) = a/g

Also, the car is making a circular motion:

a = \frac{v^2}{R}

Combining the equations:

\sin(\theta) = \frac{a}{g} = \frac{v^2/R}{g} = \frac{v^2}{gR}

Finally the angle is

\arcsin(v^2/(gR))

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Sand is pouring out of a pipe and is forming a conical pile on the ground. The radius of the pile is increasing at a rate of 2 f
Anton [14]

Answer:

a)\ V=3053.628059 \ ft^3

b)\ V'=1017.876\ ft^3/day

Explanation:

<u>Rate of Change</u>

The volume of a cone of radius r and height h is given by

\displaystyle V=\frac{\pi r^2h}{3}

The height is said to be 1/2 of the radius, thus

\displaystyle V=\frac{\pi r^2\cdot r}{2\cdot 3}

\displaystyle V=\frac{\pi r^3}{6}

a) Knowing r=18 feet, the volume is

\displaystyle V=\frac{\pi 18^3}{6}

V=3053.628059 \ ft^3

b) The rate of change of the volume is computed by taking the derivative of both sides respect to the time

\displaystyle V'=3\frac{\pi r^2}{6}r'

\displaystyle V'=\frac{\pi r^2}{2}r'

Where r' is the given rate of change of the radius: 2 feet/day.

Now we compute

\displaystyle V'=\frac{\pi 18^2}{2}\cdot 2=1017.876

\boxed{V'=1017.876\ ft^3/day}

6 0
4 years ago
Leash a block of 0.5 kg down the entire length of an inclined plane forming a name of 37 ° with the horizontal. Friction with th
castortr0y [4]
The potential energy of the block is given by:
V = m*g*h
m mass
g = 9.81m/s²
h height

The potential energy of a spring is given by:
V = 0.5 * k * x²

k spring constant
x compression of the spring

If the block starts from rest it has potential energy, but no kinetic energy. As it slides down the incline potential energy is converted into kinetic energy. When the block hits the spring the kinetic energy is converted into spring's potential energy. If the spring is fully compressed and the block is at rest again, the block has transferred all its energy into the spring. No energy is lost. So we can write:

m * g * h = 0.5 * k * x²

m = 0.5 kg
g = 9.81 m/s²
h = 2.5m * sin 37° = 1,5 m
x = 0,6 m

Solve for k.

k = 2 * m * g * h / x² = 40.8 N/m
6 0
3 years ago
How far does a car travel in 10 s if its initial velocity is 3 m/s and its acceleration
victus00 [196]

To learn more about Acceleration please visit -
brainly.com/question/13563385
#SPJ4



4 0
2 years ago
If izzy mass is 0.3kg he applide 657.9n force what will be the accelration​
Sholpan [36]

Answer:

The acceleration of the body, a = 2193 m/s²

Explanation:

Given,

The mass of the body, m = 0.3 kg

The force acting on the body, F = 657.9 N

The force acting on an object is proportional to the product of mass and acceleration of the body.

                         F = m x a

Therefore, the acceleration of the body is

                           a = F / m

                              = 657.9 N / 0.3 kg

                              = 2193 m/s²

Hence, the acceleration of the body, a = 2193 m/s²

4 0
4 years ago
Which statements define factors that contribute to the decline of Roman Empire
USPshnik [31]
The Huns' invasion of Europe caused a mass migration driving Germanic tribes of Northern Europe to the borders of the Roman Empire which led to the Barbarian attacks on Rome. 
7 0
3 years ago
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