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BlackZzzverrR [31]
3 years ago
5

Derive an expression similar to the equation for the energy levels above for the single electron in He+ and Li2+ . Calculate the

numerical values for the 1s levels (n = 1)?
Chemistry
1 answer:
VikaD [51]3 years ago
3 0

Answer:

Explanation:

from Bohr's equation,

E = -Z²R/n²

R = 13.6 eV

Z = atomic number of element

for 1s energy level n= 1

E = -(Z)² x (13.6)/(1)²

E = -13.6Z²

calculating the numerical for the 1s energy levels for He+ and Li2+

- for He+

E = -13.6 * (2)² = -54.4eV

- for Li2+

E = -13.6 * (3)² = -122.4eV

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a scuba diver's tank contains 0.29g of oxygen compressed into volume of 2.3L. What is the pressure in the tank at 9C?
viva [34]

Answer:

The answer to your question is P = 0.18 atm

Explanation:

Data

mass of O₂ = 0.29 g

Volume = 2.3 l

Pressure = ?

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constant of ideal gases = 0.082 atm l/mol°K

Process

1.- Convert the mass of O₂ to moles

                16 g of O₂ -------------------- 1 mol

                0.29 g of O₂ ----------------   x

                    x = (0.29 x 1)/16

                    x = 0.29/16

                    x = 0.018 moles

2.- Convert the temperature to °K

Temperature = 9 + 273 = 282°K

3.- Use the ideal gas law ro find the answer

              PV = nRT

-Solve for P

              P = nRT/V

-Substitution

              P = (0.018 x 0.082 x 282) / 2.3

-Simplification

              P = 0.416/2.3

-Result

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What is the mass of silver (107.87 g/mol) produced by the reaction of 3.00 moles of copper with 3.00 moles of silver nitrate?Cu
vladimir2022 [97]

Answer: 323.61 g of Ag will be produced

Explanation:

The given balanced chemical reaction is :

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According to stoichiometry :

2 moles of AgNO_3 require 1 mole of Cu

Thus 3.00 moles of  AgNO_3 will require=\frac{1}{2}\times 3.00=1.50moles  of Cu

Thus AgNO_3 is the limiting reagent as it limits the formation of product.

As 2 moles of AgNO_3 give =  2 moles of Ag

Thus 3.00 moles of AgNO_3 give =\frac{2}{2}\times 3.00=3.00moles  of Ag

Mass of Ag=moles\times {\text {Molar mass}}=3.00moles\times 107.87g/mol=323.61g

Thus 323.61 g of Ag will be produced from the given moles of both reactants.

3 0
3 years ago
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