1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Leno4ka [110]
3 years ago
13

Why do the gases on the periodic table tend to form negative ions?

Chemistry
1 answer:
boyakko [2]3 years ago
8 0
Because the valence shell of gases wants to become full
You might be interested in
PLEASE HELP ME 10 POINTS
Shkiper50 [21]
My best guess is shame

6 0
4 years ago
Read 2 more answers
How to set up the rate expressions for the following mechanism?
Anestetic [448]

Answer:

Explanation:

From the given information:

A → B k₁

B → A k₂

B + C → D k₃

The rate law = \dfrac{d[D]}{dt}=k_3[B][C] --- (1)

\dfrac{d[B]}{dt}=k[A] -k_2[B] -k_3[B][C]

Using steady-state approximation;

\dfrac{d[B]}{dt}=0

k_1[A]-k_2[B]-k_3[B][C] = 0

[B] = \dfrac{k_1[A]}{k_2+k_3[C]}

From equation (1), we have:

\mathbf{\dfrac{d[D]}{dt}= \dfrac{k_3k_1[A][C]}{k_2+k_3[C]}}

when the pressure is high;

k₂ << k₃[C]

\dfrac{d[D]}{dt} = \dfrac{k_3k_1[A][C]}{k_3[C]}= k_1A \ \  \text{first order}

k₂ >> k₃[C]

\dfrac{d[D]}{dt} = \dfrac{k_3k_1[A][C]}{k_2}= \dfrac{k_1k_3}{k_2}[A][C] \ \  \text{second order}

3 0
3 years ago
We can change a gas to liquid by_________ the temperature and_________
Tpy6a [65]
Decreasing, Removing
6 0
3 years ago
Which beakers in the model contain solid insoluble substances?
ladessa [460]
Although the models are not provided, I was able to find them and the beakers with solid present in them are:
1C
2A
2C
3A
3C

This is determined by the fact that the beakers all have a piece of closely packed substance laying at the bottom. This closely packed lattice is characteristic of solid substances, and the fact that they exist in the solution in the solid states indicates that they are insoluble.
7 0
4 years ago
Select all that apply. Catalysts can save money by essentially lowering the:
k0ka [10]

Answer: Options (a) and (d) are the correct answer.

Explanation:

A catalyst is the substance which helps in increasing the rate of reaction.

Activation energy is the minimum amount of energy required by reactants to start the reaction. On addition of catalyst, the path of reaction changes because the energy barrier gap reduces and hence, the activation energy also decreases.

In the absence of catalyst, we need to increase the temperature so that reaction can occur quickly.

Whereas on addition of catalyst, there is no need to increase the temperature as the catalyst itself is sufficient to increase the rate of reaction. As a result, temperature should be lowered when there is addition of catalyst in the reaction.

Thus, we can conclude that catalysts can save money by essentially lowering the activation energy and temperature required.


4 0
3 years ago
Read 2 more answers
Other questions:
  • Which values are written in proper scientific notation? Check all that apply. –350 –350.00 –3.50 × 104 0.000350 3.50 × 104 3.50
    15·2 answers
  • Write briefly how oxygen gas is prepared in the industry​
    6·1 answer
  • Water is an example of a(n) _______?
    11·1 answer
  • When potassium chlorate decomposes to potassium chloride and oxygen gas is it a physical or chemical change?
    8·1 answer
  • A particle has a mass of 2 × 10-30 kg and an uncertainty in its velocity of 102 m/s. What is the minimum possible uncertainty in
    5·1 answer
  • On the graph, which shows the potential energy curve of two N atoms, carefully sketch a curve that corresponds to the potential
    5·1 answer
  • Identify the correct formula for ammonia.
    7·1 answer
  • What is the balanced equation for the reaction of lithium metal with fluorine gas? Li ( s ) + F ( g ) → LiF ( s ) Li ( s ) + F 2
    12·1 answer
  • What would be the mass of 3 moles of water molecules?
    9·2 answers
  • You plan to use the water displacement method to
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!