Answer:
I would expect to extract the acetic acid.
Explanation:
In the first step, since we are adding a concentrated acid,<u> it will react with the bases present in the mixture (diethylamine and ammonia) </u><u>forming salts</u><u>, </u><u>which are soluble in water</u>. Therefore, after draining the aqueous layer, we will have phenol and acetic acid left in the organic layer.
In the second step, we are adding a diluted base, so it will react with a strong acid. This compound is acetic acid, and its salt will be present in the aqueous layer. Phenol will be left on the organic layer.
Answer:
0.823 M was the molarity of the KOH solution.
Explanation:
(Neutralization reaction)
To calculate the concentration of base , we use the equation given by neutralization reaction:
where,
are the n-factor, molarity and volume of acid which is 
are the n-factor, molarity and volume of base which is KOH.
We are given:
Putting values in above equation, we get:
0.823 M was the molarity of the KOH solution.
Answer:
n = 2
l = 1
m = 1
s = +1/2
Explanation:
₇N tiene la configuración electrónica;
1s2 2s2 2p3
Esto implica que este último electrón tiene los siguientes números cuánticos;
n = 2
l = 1
m = 1
s = +1/2
Este último electrón estará en un orbital de 2pz como lo muestran los números cuánticos enumerados anteriormente.
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