Answer: The different quantities of eggs are: grade aa, grade a and grade b. The different quantities of an egg are: hard & soft boiled, hard & soft scrambled, sunny side up and over easy-over hard.
Explanation: hope it helps
Answer: Concentration of HI is present at equilibrium is 1.26 M
Explanation:
Moles of
= 0.800 mole
Moles of
= 0.800 mole
Volume of solution = 1.00 L
Initial concentration of
= 0.800 M
Initial concentration of
= 0.800 M
The given balanced equilibrium reaction is,

Initial conc. 0.800 0.800 0
At eqm. conc. (0.800-x) M (0.800-x) M (2x) M
The expression for equilibrium constant for this reaction will be,
![K_c=\frac{[HI]^2}{[H_2]\times [l_2]}](https://tex.z-dn.net/?f=K_c%3D%5Cfrac%7B%5BHI%5D%5E2%7D%7B%5BH_2%5D%5Ctimes%20%5Bl_2%5D%7D)
Now put all the given values in this expression, we get :

By solving the term 'x', we get :
x = 0.63
Concentration of
at equilibrium = 2 x = 
Concentration of HI is present at equilibrium is 1.26 M
Hey there
the answer is A. Atoms of the same element can have different number of neutrons
thank you gurl
Answer:
The wavelength of these photons will become longer. The energy of each of these photons will become lower.
Explanation:
<h3>Wavelength</h3>
Light can be considered as electromagnetic waves. The wavelength of a wave is equal to the minimum distance between two troughs (lowest points) in this wave. On the other hand, the frequency of a wave is equal to the number of wavelengths that this wave travels in unit time.
Assume that the speed of light stays the same. The distance that this beam of light travels in unit time will be the same. However, with a lower frequency, there would be fewer wavelengths in that same distance. Therefore, the size of each wavelength will become longer.
If
represent the speed of light and
represents the frequency, then the wavelength would be:
.
<h3>Energy</h3>
The energy
of each proton of a beam of light is proportional to the frequency
of the light. Let
denote Planck's Constant. The numerical relation between
and
would be:
.
Therefore, if the frequency
of this light becomes smaller, the energy
of each of its proton will also become proportionally lower.