Answer:
1C₆H₁₂O₆(s) + 6O₂(g) → 6CO₂(g) + 6H₂O(l)
Explanation:
In general equation combustions where all carbon produce CO₂ and all hydrogen H₂O we must begin the balance with these two species:
_C₆H₁₂O₆(s) + _O₂(g) → _CO₂(g) + _H₂O(l)
If sugar is 1, CO₂ and H₂O must be:
1C₆H₁₂O₆(s) + _O₂(g) → 6CO₂(g) + 6H₂O(l)
Thus, C and H are balanced. In the right side we have 12 oxygen from CO₂ + 6 oxygen from H₂O = 18 oxygen
In the left there are 6, thus, O₂ must provide 12 oxygens, thus:
<h3>
1C₆H₁₂O₆(s) +
6O₂(g) →
6CO₂(g) +
6H₂O(l)</h3>
And this is the balanced reaction
Answer:
The answer is "3".
Explanation:
acetic acid Dissociation:
Dissociation constant of the Ka:
![Ka = \frac{[CH3COO^{-}] [H^{+}]}{[CH_3COOH]}\\\\](https://tex.z-dn.net/?f=Ka%20%3D%20%5Cfrac%7B%5BCH3COO%5E%7B-%7D%5D%20%5BH%5E%7B%2B%7D%5D%7D%7B%5BCH_3COOH%5D%7D%5C%5C%5C%5C)
using the ICE table:
x is negligible compared to Ka.
![1.8\times 10^{-5} = \frac{x^2}{0.10}\\\\x^2 = 1.8 \times 10^{-6}\\\\x = 1.34 \times 10^{-3}\\\\pH = -\log [H^{+}]](https://tex.z-dn.net/?f=1.8%5Ctimes%2010%5E%7B-5%7D%20%3D%20%5Cfrac%7Bx%5E2%7D%7B0.10%7D%5C%5C%5C%5Cx%5E2%20%3D%201.8%20%5Ctimes%2010%5E%7B-6%7D%5C%5C%5C%5Cx%20%3D%201.34%20%5Ctimes%2010%5E%7B-3%7D%5C%5C%5C%5CpH%20%3D%20-%5Clog%20%5BH%5E%7B%2B%7D%5D)
From the ICE table, ![[H^{+}] = x = 1.34 \times 10^{-3}](https://tex.z-dn.net/?f=%5BH%5E%7B%2B%7D%5D%20%3D%20x%20%3D%201.34%20%5Ctimes%2010%5E%7B-3%7D)
2 PO₄³⁻ (aq) + 3 Co²⁺ (aq) → Co₃(PO₄)₂ (s)
Explanation:
molecular equation:
2 Na₃PO₄ + 3 CoCl₂ → Co₃(PO₄)₂ + 6 NaCl
ionic equation:
6 Na⁺ (aq) + 2 PO₄³⁻ (aq) + 3 Co²⁺ (aq) + 6 Cl⁻ (aq) → Co₃(PO₄)₂ (s) + 6 Na⁺ (aq) + 6 Cl⁻ (aq)
we remove the spectator ions to get the net ionic equation:
2 PO₄³⁻ (aq) + 3 Co²⁺ (aq) → Co₃(PO₄)₂ (s)
were:
(aq) - aqueous
(s) - solid
Learn more about:
net ionic equation
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Answer: The average atomic mass of nitrogen is 14.0066 amu
Explanation:
Mass of isotope N-14 = 14.00307 amu
% abundance of isotope N-14= 99.64% = 
Mass of isotope N-13 = 15.0001 amu
% abundance of isotope N-13= (0.36)% = 
Formula used for average atomic mass of an element :
![A=\sum[(14.00307)\times \frac{99.64}{100})+(15.0001)\times \frac{0.36}{100}]]](https://tex.z-dn.net/?f=A%3D%5Csum%5B%2814.00307%29%5Ctimes%20%5Cfrac%7B99.64%7D%7B100%7D%29%2B%2815.0001%29%5Ctimes%20%5Cfrac%7B0.36%7D%7B100%7D%5D%5D)
Therefore, the average atomic mass of nitrogen is 14.0066 amu
Answer:
moving it to a drier climate
Explanation:
Drier climate and higher temperature make more chemical weathering occur quicker.
