Moles Li = 3.50 g / 6.941 g/mol= 0.504
the ratio between Li and N2 is 6 : 1
moles N2 required = 0.504 /6=0.0840
we have 3.50 g / 28.0134 g/mol=0.125 moles of N2 so N2 is in excess
the ratio between Li and Li3N is 6 : 2
moles Li3N = 0.504 x 2 /6=0.168
mass Li3N = 0.168 mol x 34.8297 g/mol=5.85 g
Answer:
A
Explanation:
a compound is a pure substance and A tells that
Answer:
12
Explanation:
Boyles law
P1 (.36)
V1(28.3)
P2(.85)
V2(?)
P1*V1=P2*V2
plug it in, and you get 12
Molecular weight of m is 40g. Hence, name of element m is Calcium. which is represented by the symbol Ca.
Given,
Moles of metal M = 0.300 moles
weight of mF₂ formed =23.4g
we have to find the name of element m...
Now,
m + F₂ → mF₂
1 mole of m reacts with 1 mole of F₂ (or 2 molecule of flourine) to form 1 mole of mF₂
Hence,
0.300 moles of m reacts with 0.300 moles of F₂ to form 0.300 moles of mF₂.
Hence,
23.4 g = 0.300 moles of mf2
0.300 × 38g + 0.300 × m = 23.4 g
Hence
m = 40 g
So, molecular weight of m is 40g. Hence, name of element m is Calcium. which is represented by the symbol Ca.
Thus, from the above conclusion we can say that, name of element m is Calcium. which is represented by the symbol Ca.
Learn more about Calcium here:brainly.com/question/26636816
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