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Diano4ka-milaya [45]
3 years ago
14

700 is 10 times as much as

Chemistry
2 answers:
pogonyaev3 years ago
6 0
700 is ten times munch as 70
nevsk [136]3 years ago
3 0
<span>700 is 10 times as much as 70

</span>
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When 47.1 J of heat is added to 14.0 g of a liquid, its temperature rises by 1.80 ∘C. What is the heat capacity of the liquid?
Alja [10]

Answer:

\boxed {\boxed {\sf 1.87 \J/g \textdegree C}}

Explanation:

We are asked to find the specific heat capacity of a liquid. We are given the heat added, the mass, and the change in temperature, so we will use the following formula.

q= mc\Delta T

The heat added (q) is 47.1 Joules. The mass (m) of the liquid is 14.0 grams. The specific heat (c) is unknown. The change in temperature (ΔT) is 1.80 °C.

  • q= 47.1 J
  • m= 14.0 g
  • ΔT= 1.80 °C

Substitute these values into the formula.

47.1 \ J = (14.0 \ g) * c * (1.80 \textdegree C)

Multiply the 2 numbers in parentheses on the right side of the equation.

47.1 \ J = (14.0 \ g * 1.80 \textdegree C)*c

47.1 \ J = (25.2 \ g*\textdegree C) *c

We are solving for the heat capacity of the liquid, so we must isolate the variable c. It is being multiplied by 25.2 grams * degrees Celsius. The inverse operation of multiplication is division, so we divide both sides of the equation by (25.2 g * °C).

\frac {47.1 \ J}{(25.2 g *\textdegree C)} = \frac {(25.2 g *\textdegree C)*c}{{(25.2 g *\textdegree C)}}

\frac {47.1 \ J}{(25.2 g *\textdegree C)} =c

1.869047619 \ J/g *\textdegree C = c

The original measurements of heat, mass, and temperature all have 3 significant figures, so our answer must have the same. For the number we found that is the hundredth place. The 9 in the thousandth place to the right tells us to round the 6 up to a 7.

1.87 \ J/ g * \textdegree C =c

The heat capacity of the liquid is approximately 1.87 J/g°C.

3 0
3 years ago
A.explain what is meant by term
mrs_skeptik [129]

Answer:

Explanation:

1. Atomic numbers:

Atomic number is the number of protons in an atom. It is one of the most diagonistic and representative number used in identifying an atom. The periodic table of element arranges elements based on this number.

No two elements have the same atomic number.

Protons are positively charged particles in an atom.

  • In a neutral atom, the atomic number is the same as the number electrons since electrical neutrality is attained when the number of protons and electrons are the same.
  • The atomic number determines the position of an atom on the periodic table and it is unique for every atom.

2.

Periodic patterns

These are trends on that can be predicted on the periodic table because they shew regularities down a group or sometimes across the period.

Some of these trends are atomic radius, electronegativity, metallicity, nuclear charge e.t.c

Properties of elements can be predicted using these patterns even before they are discovered.

b.

Physical property shared by Helium, Argon and Neon is that they are all gases. All group 8 elements are called noble or inert gases.

Chemical property of these elements: they are chemically unreactive.

These gases are very stable having complete electronic shell configuration. Every atom on the periodic table tries to attain the state of the noble gases.

C.

Noble Gases/ Inert Gases/ Group O elements

6 0
3 years ago
How much heat will be released when 10.0 g of hydrogen peroxide decomposes according to the following reaction: 2H2O2(l) 2H2O(l)
kramer
C. 28 KJ

AMU of H2O2 = 2(1) + 2(16) = 34 g/mol
10 g / 34 g/mol = 0.294 mol H2O2

0.294 mol / H = 2 mol / 190 KJ
H = 28.9 KJ
5 0
4 years ago
In which of these systems is the entropy decreasing?
Delicious77 [7]
"A <span>gas condensing to a liquid" is the one system among the following choices given in the question where the entropy is decreasing. The correct option among all the options that are given in the question is the fourth option or option "D". I hope that this is the answer that has come to your desired help.</span>
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4 years ago
Is h3co3 a strong base
tamaranim1 [39]
I read and said it's a weak base
3 0
3 years ago
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