Answer:
303.6 mg
Explanation:
Given that:
The lethal dose
= 1320 mg/kg
The weight of the rat = 230 g
The lethal dose is the dose of a substance likely to cause death. SO a lethal dose of 50 will cause the death of 50% of the sample of test animals.
Therefore;
The mass of 2-naphthol that would have been ingested by each rat in a sample set of rats in order to kill half the population of rats will be equal to:
![=\dfrac{LD_{50}}{1000} \times wt \ of \ rat](https://tex.z-dn.net/?f=%3D%5Cdfrac%7BLD_%7B50%7D%7D%7B1000%7D%20%5Ctimes%20wt%20%20%5C%20%20of%20%20%5C%20rat)
![=\dfrac{1320}{1000}\times 230](https://tex.z-dn.net/?f=%3D%5Cdfrac%7B1320%7D%7B1000%7D%5Ctimes%20230)
= 303.6 mg
The answer to this question is that the percentage by volume of a hyrdrogen peroxide in mostly first aid kits contains 3%. Hydrogen peroxide or H2O2 is a compound that can be used as an antiseptic in orderto prevent infections from spreading in the bruises, cuts, and even burns. Hydrogen peroxide can also be used as a bleaching agent and an oxidizer.
Answer:
the process begins in the cloroplast and is completed in the mitocondria
Answer:
<h2>2.57 g/mL</h2>
Explanation:
The density of a substance can be found by using the formula
![density = \frac{mass}{volume}\\](https://tex.z-dn.net/?f=density%20%3D%20%20%5Cfrac%7Bmass%7D%7Bvolume%7D%5C%5C)
From the question we have
volume = final volume of water - initial volume of water
volume = 22.76 mL - 15.35 ml = 7.41 mL
![density = \frac{19.060}{7.41} \\ = 2.572199](https://tex.z-dn.net/?f=density%20%3D%20%20%5Cfrac%7B19.060%7D%7B7.41%7D%20%20%5C%5C%20%20%3D%202.572199)
We have the final answer as
<h3>2.57 g/mL</h3>
Hope this helps you