All categories

2 years ago

Which is the first news paper of Nepal

Chemistry

1 answer:

Airida [17]2 years ago

3 0

Answer:

Nepal Bhasa Patrika

Explanation:

Nepal Bhasa Patrika

You might be interested in

Which electron dot diagram represents H2?

Marizza181 [45]

Answer:

H:H

Explanation:

7 0

2 years ago

Find the pH of a solution whose H concentration is 0.7 x 10-3.

dexar [7]

Answer: pH = 3.15

Explanation: Solved in the attached picture.

6 0

2 years ago

In the ground state, an atom of which element has seven valence

sweet-ann [11.9K]

Answer:

Fluorine

Explanation:

Fluorine has 9 total electrons. The first two are in the 1s level, and the remaining electrons are on the outer level of the atom, with 2 in the s level and 5 in the p level. The electron configuration is 1s2 2s2 2p5.

7 0

2 years ago

Convert 100,000,00. milligrams to kilograms

aivan3 [116]

Answer:milliliters to kilograms

Weight of 1000 milliliters (ml) of pure water at temperature 4 °C = 1 kilogram (kg).

Explanation:

hope this helps have a nice night ❤️❤️❤️

3 0

2 years ago

A chemist uses hot hydrogen gas to convert chromium(III) oxide to

Darya [45]

Answer: 3.024 g grams of hydrogen are needed to convert 76 grams of chromium(III) oxide, $Cr_{2}O_{3}$

Explanation:

The reaction equation for given reaction is as follows.

$Cr_{2}O_{3} + 3H_{2} \rightarrow 2Cr + 3H_{2}O$

Here, 1 mole of $Cr_{2}O_{3}$ reacts with 3 moles of $H_{2}$ .

As mass of chromium (III) oxide is given as 76 g and molar mass of chromium (III) oxide $(Cr_{2}O_{3})$ is 152 g/mol.

Number of moles is the mass of substance divided by its molar mass. So, moles of $Cr_{2}O_{3}$ is calculated as follows.

$No. of moles = \frac{mass}{molar mass}\\= \frac{76 g}{152 g/mol}\\= 0.5 mol$

Now, moles of $H_{2}$ .given by 0.5 mol of $Cr_{2}O_{3}$ is calculated as follows.

$0.5 mol Cr_{2}O_{3} \times \frac{3 mol H_{2}}{1 mol Cr_{2}O_{3}}\\= 1.5 mol H_{2}$

As molar mass of $H_{2}$ is 2.016 g/mol. Therefore, mass of $H_{2}$ is calculated as follows.

$No. of moles = \frac{mass}{molar mass}\\1.5 mol = \frac{mass}{2.016 g/mol}\\mass = 3.024 g$

Thus, we can conclude that 3.024 g grams of hydrogen are needed to convert 76 grams of chromium(III) oxide, $Cr_{2}O_{3}$ .

7 0

2 years ago

Which is the first news paper of Nepal​

Which is the first news paper of Nepal