Convert 1.2030 moles of sodium chloride to grams

Chemistry

2 answers:

vazorg [7]3 years ago

5 0

70.306 would be your answer.

Nikolay [14]3 years ago

4 0

You take the moles and multiply by the molar mass

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At 311 K, this reaction has a K c value of 0.0111 . X ( g ) + 2 Y ( g ) − ⇀ ↽ − 2 Z ( g ) Calculate K p at 311 K. Note that the

Aleks [24]

Answer:

$K_{p}=4.35\times 10^{-4}$

Explanation:

We know, $K_{p}=K_{c}(RT)^{\Delta n}$

where, R = 0.0821 L.atm/(mol.K), T is temperature in kelvin and $\Delta n$ is difference in sum of stoichiometric coefficient of products and reactants

Here $\Delta n=(2)-(2+1)=-1$ and T = 311 K

So, $K_{p}=(0.0111)\times [(0.0821L.atm.mol^{-1}.K^{-1})\times 311K]^{-1}=4.35\times 10^{-4}$

Hence value of equilibrium constant in terms of partial pressure $(K_{p})$ is $4.35\times 10^{-4}$

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3 years ago

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7 0

2 years ago

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kkurt [141]

Answer: The $\Delta H^o_{rxn}$ for the reaction is 72 kJ.

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The given chemical reaction follows:

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