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AnnZ [28]
2 years ago
6

The medium for ocean waves

Chemistry
1 answer:
stepladder [879]2 years ago
7 0
This is a tough one but the answer is water

think of it this way the ocean is water
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Someone please help me!!
Anna007 [38]

Explanation: D and G

             

4 0
3 years ago
What is the molar mass of Fe(NO3)2?
motikmotik
I believe that the molar mass is 342.34g/mol
5 0
3 years ago
How many liters of carbon dioxide will 0.5 moles of lithium hydroxide (LiOH) absorb?
Elden [556K]

Answer : The volume of carbon dioxide will be, 5.6122 L

Solution : Given,

Moles of LiOH = 0.5 moles

Molar mass of carbon dioxide = 44 g/mole

Density of carbon dioxide = 0.00196 g/ml

First we have to calculate the mass of carbon dioxide.

The balanced reaction will be,

2LiOH+CO_2\rightarrow Li_2CO_3+H_2O

From the reaction we conclude that

As, 2 moles of LiOH absorbs 44 grams of carbon dioxide

So, 0.5 moles of LiOH absorbs \frac{0.5moles}{2moles}\times 44g=11 grams of carbon dioxide

Mass of carbon dioxide = 11 g

Density of carbon dioxide = 0.00196 g/ml

Now we have to calculate the volume of carbon dioxide.

Density=\frac{Mass}{volume}

0.00196g/ml=\frac{11g}{volume}

Volume of carbon dioxide = 5612.24 ml = 5.6122 L      (1 L = 1000 ml)

Therefore, the volume of carbon dioxide will be, 5.6122 L

5 0
2 years ago
If you are correct you get a brainless
LenKa [72]
In a non-flowering plant, the embryo is in spores found in the stem, and in a flowering plant, the embryo is in seeds found in the flower.
(don’t count on my answer but I think it might be this one and I apologize if you get it wrong)
6 0
3 years ago
When the following oxidation–reduction reaction in acidic solution is balanced, what is the lowest whole-number coefficient for
Svet_ta [14]

Answer:

c. 8, product side

Explanation:

In order to balance a redox reaction we use the ion-electron method, which has the following steps:

Step 1: identify oxidation and reduction half-reaction.

Oxidation: MnO₄⁻(aq) → Mn²⁺(aq)

Reduction: Br⁻(aq) → Br₂(l)

Step 2: perform the mass balance adding H⁺ and H₂O where necessary

8 H⁺(aq) + MnO₄⁻(aq) → Mn²⁺(aq) + 4 H₂O(l)

2 Br⁻(aq) → Br₂(l)

Step 3: perform the electrical balance adding electrons where necessary.

8 H⁺(aq) + MnO₄⁻(aq) + 5 e⁻ → Mn²⁺(aq) + 4 H₂O(l)

2 Br⁻(aq) → Br₂(l) + 2 e⁻

Step 4: multiply both half-reactions by numbers that secure that the number of electrons gained and lost are the same.

2 × (8 H⁺(aq) + MnO₄⁻(aq) + 5 e⁻ → Mn²⁺(aq) + 4 H₂O(l))

5 × (2 Br⁻(aq) → Br₂(l) + 2 e⁻)

Step 5: add both half-reactions side to side.

16 H⁺(aq) + 2 MnO₄⁻(aq) + 10 e⁻ + 10 Br⁻(aq) → 2 Mn²⁺(aq) + 8 H₂O(l) + 5 Br₂(l) + 10 e⁻

16 H⁺(aq) + 2 MnO₄⁻(aq) + 10 Br⁻(aq) → 2 Mn²⁺(aq) + 8 H₂O(l) + 5 Br₂(l)

3 0
2 years ago
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