If the question is true or false then the answer is true
Answer:
a) Posición y velocidad después de los 6s
i) Posición = -26.58m
ii) velocidad = -33.86m/s
b) Tiempo para alcanzar la altura máxima
= 2.55s
c) Alcance horizontal
= 220.7m
Explanation:
a) Posición y velocidad después de los 6s
i) Posición
y = (usinθ)t – 1/2 gt²
u = 50m/s
θ = 30°
g = 9.81m/s²
t = 6s
y = (50 × sin 30)6 - 1/2 × 9.81 × 6²
y = 150 - 176.58
y = -26.58m
ii) velocidad
v = u sinθ–gt
u = 50m/s
θ = 30°
g = 9.81m/s²
t = 6s
v = 50 × sin 30 - 9.81 × 6
v = 25 - 58.86
v = -33.86m/s
b) Tiempo para alcanzar la altura máxima
usinθ /g
u = 50m/s
θ = 30°
g = 9.81m/s²
= 50 × sin 30/ 9.81
= 25/9.81
= 2.5484199796s
≈ 2.55s
c) Alcance horizontal
R = u²sin2θ/g
u = 50m/s
θ = 30°
g = 9.81m/s²
R = 50² ×( sin 2 ×30°) /9.81
R = 220.69964419m
≈ 220.7m
Answer:
q=3.5*10^-4
Explanation:
<u>concept:</u>
The force acting on both charges is given by the coulomb law:
F=kq1q2/r^2
the centripetal force is given by:
Fc=mv^2/r
The kinetic energy is given by:
KE=1/2mv^2
<u>The tension force:</u>
<u><em>when the plane is uncharged </em></u>
T=mv^2/r
T=2(K.E)/r
T=2(50 J)/r
T=100/r
<u><em>when the plane is charged </em></u>
T+k*|q|^2/r^2=2(K.E)charged/r
100/r+k*|q|^2/r^2=2(53.5 J)/r
q=√(2r[53.5 J-50 J]/k) √= square root on whole
q=√2(2)(53.5 J-50 J)/8.99*10^9
q=3.5*10^-4
Temperature lower than absolute zero is not possible. Lower than absolute zero a gas contain negative pressure and volume which is not possible. temperature is the energy created by moving atoms absolute zero is a complete stand still you can make particles move to the end of the universe but the coldest temperature will be stuck at the point where atoms are motionless
hope that helped :)