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nika2105 [10]
3 years ago
14

A car accelerates uniformly from +10.0 m/s to +40.0 m/s over a distance of 125 m. How long did it take to go that distance? Show

all your work, including the equation used, given and unknown quantities, and any algebra required. Make sure your answer has the correct number of significant figures.
Physics
1 answer:
Marizza181 [45]3 years ago
7 0

Answer:

Explanation:

v^2-u^2=2as\\40^2-10^2=2a*125\\1600-100=250a\\a=\frac{1500}{250}=6~m/s^2\\v=u+at\\40=10+6t\\6t=30\\ t=\frac{30}{6}=5 ~s

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1) p₀ = 0.219 kg m / s, p = 0, 2)  Δp = -0.219 kg m / s, 3) 100%

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            Em₀ = U = mg y

Final. Low point just before the crash

           Emf = K = ½ m v²

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Let's calculate

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           v = 0.99 m / s

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After the collision, the car's speed is zero, so its moment is zero.

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