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nika2105 [10]
3 years ago
14

A car accelerates uniformly from +10.0 m/s to +40.0 m/s over a distance of 125 m. How long did it take to go that distance? Show

all your work, including the equation used, given and unknown quantities, and any algebra required. Make sure your answer has the correct number of significant figures.
Physics
1 answer:
Marizza181 [45]3 years ago
7 0

Answer:

Explanation:

v^2-u^2=2as\\40^2-10^2=2a*125\\1600-100=250a\\a=\frac{1500}{250}=6~m/s^2\\v=u+at\\40=10+6t\\6t=30\\ t=\frac{30}{6}=5 ~s

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          - G m M / R² = m ( - \frac{4\pi^2 R^2  }{T^2 R})

         G M = \frac{ 4\pi ^2 R^3  }{T^2 }

         M = \frac{4 \pi ^2 R^3 }{ G T^2 }

the distance R is the distance from the center of the planet Mars to the center of the satellite Deimos

         R = 23460 km = 2.3460 10⁷ m

the period of the orbit is

         T = 1,263 days = 1,263 day (24 h / 1 day) (3600s / h)

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let's calculate

          M = \frac{4 \pi ^2  ( 2.3460 \ 10^7)^3 }{5.67 10^{-11} \ (1.0912 \ 10^5)^2 }

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          M = 58.817 10²² kg

          M = 5.882 10²³ kg

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