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JulijaS [17]
2 years ago
11

FCFrdfAQefgEwdfgedfsaewfdedasfewreagargferdfares

Physics
2 answers:
Ivan2 years ago
6 0

Answer: AAAAAAAAGGGGGHHHHJJJGSSSUUUUUUUUYCCFVGBHNJM

Explanation: YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET

melomori [17]2 years ago
6 0

Answer:

THANK YOU FOR THE POINTS RANDOM PERSON

Explanation:

you are very nice thank you also...ADB WHBCJABCIWBECJ   Uzw qXUYHjQhyvUhbsdfgvvYTVhvUveeeee

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A 1.50-V battery supplies 0.414 W of power to a small flashlight. If the battery moves 4.93 1020 electrons between its terminals
slamgirl [31]

Answer:

2.86×10⁻¹⁸ seconds

Explanation:

Applying,

P = VI................ Equation 1

Where P = Power, V = Voltage, I = Current.

make I the subject of the equation

I = P/V................ Equation 2

From the question,

Given: P = 0.414 W, V = 1.50 V

Substitute into equation 2

I = 0.414/1.50

I = 0.276 A

Also,

Q = It............... Equation 3

Where Q = amount of charge, t = time

make t the subject of the equation

t = Q/I.................. Equation 4

From the question,

4.931020 electrons has a charge of (4.931020×1.6020×10⁻¹⁹) coulombs

Q = 7.899×10⁻¹⁹ C

Substitute these value into equation 4

t =  7.899×10⁻¹⁹/0.276

t = 2.86×10⁻¹⁸ seconds

5 0
3 years ago
A particle of charge Q is fixed at the origin of an xy coordinate system. At t = 0 a particle (m = 0.727 g, q = 2.73 µC is locat
Montano1993 [528]

Answer:

Q = 12.466μC

Explanation:

For the particle to execute a circular motion, the electrostatic force must be equal to the centripetal force:

Fe = \frac{K*q*Q}{r^{2}} = \frac{m*V^{2}}{r}

Solving for Q:

Q = \frac{m*V^{2}*r}{K*q}

Taking special care of all units, we can calculate the value of the charge:

Q = 12.466μC

5 0
3 years ago
With which of the following is the weak nuclear force associated
BaLLatris [955]
You need to post a picture bro
5 0
2 years ago
At a dock, a crane lifts a 2009 kg container 20 m, swings it out over the deck of a freighter, and lowers the container into the
deff fn [24]

Answer:

W = 157.5kJ

Explanation:

Assuming it moves the container at constant speed, the work done by the crane will be equal to the variation of the potential gratitational energy on the container:

Wc = \Delta E = m*g*(h2 - h1)  where h2= -8m  and  h1=0m

Wc = 157.5kJ

6 0
3 years ago
A hard drive has 250 gigabytes of storage?
Dafna11 [192]
A. 0.25 terabytes
b. 2.5e + 17
4 0
3 years ago
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