Answer:
a. i. 30 Nm ii. This moment is a clockwise positive moment.
b. i. 15 Nm ii, This moment is a counter-clockwise negative moment.
c. i. The plank will not balance. ii. The plank would tip up.
d. 150 N
Explanation:
a) Calculate the moment of the 60N force (about O), then name its type.
i. Calculate the moment of the 60N force (about O)
Since moment = Force × perpendicular distance from point of moment ,
M = Fd
Since F = 60 N and d = 50 cm = 0.5 m
M = 60 N × 0.5 m = 30 Nm
ii. Then name its type.
This moment is a clockwise positive moment.
b) Calculate the moment of the 30N force (about O), then name its type.
i. Calculate the moment of the 30N force (about O),
Since moment = Force × perpendicular distance from point of moment ,
M' = F'd'
Since F' = 30 N and d' = 50 cm = 0.5 m
M' = 30 N × 0.5 m = 15 Nm
ii. Then name its type.
This moment is a counter-clockwise negative moment.
c) Will the plank balance? If not, which way will it tip?
i. Will the plank balance?
The plank will balance if the net moment on it is zero
So net moment, M' = positive moment - negative moment = M - M' = 30 Nm - 15 Nm = 15 Nm
Since the net moment on the plank is M" = 15 Nm ≠ 0,<u>the plank will not balance.</u>
ii Which way will it tip?
The plank would tip in the direction of the greater moment since the net moment is positive. <u>This moment tilts the plank in a clockwise direction, so the plank would tip up.</u>
d) What extra force would be needed at (B) to balance the plank?
The extra force must balance the net moment,
So M" = F"d" where F" = force and d" = distance of force from O = 10 cm = 0.10 m
F" = M"/d"
= 15 Nm/0.10 m
= 150 N
