I think you want to determine the exit speed?
You have to determine how much velocity was decreased by calculating it from the kinetic energy.
KE = (1/2)mv²
1.4 x 10^5 = (1/2)*(1100)v²
v² = 254.55
v =15.95 m/s
So the velocity reduces by 15.95 m/s. Subtracting this to the initial velocity: 22 - 15.95 = 6.05 m/s.
So, the final speed was 6.05 m/s.
I hope I was able to help :)
Answer:
23.5 m/s
Explanation:
The velocity of the car in decelerated motion is given by
v = u + at
where
v = 0 is the final velocity
u is the initial velocity
a is the acceleration of the car
t = 3.0 s is the time it takes for the car to stop
The acceleration of the car is given by the frictional force, which is the only force acting on the car along the direction of motion, so:

where
is the coefficient of friction
Solving the previous equation for u, we find the initial velocity:

A scalar quantity is one in which there is no direction given.
30 Lbs would be the answer, since there is no indicator of direction.