For the sound wave passing through regions of the ocean with varying density, longer wavelengths correspond to greater density of the water.
<h3>What is effect of density of a medium on wavelength of a wave?</h3>
The density of a medium is directly proportional to the wavelength of a wave.
The higher the density of the medium, the longer the wavelength of a wave.
Therefore, for a sound wave passing through regions of the ocean with varying density, longer wavelengths correspond to greater density of the water.
Learn more about density and wavelength at: brainly.com/question/9486264
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The FREQUENCY of light remains unchanged once it leaves the source.
The reactants are <em>Calcium</em>, <em>Hydrogen</em> and <em>Oxygen</em>.
We need 1 atom of <em>Calcium</em>, 4 atoms of <em>Hydrogen</em> and 2 atoms of <em>Oxygen</em>.
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r3t40
Average velocity over a given time interval is the distance traveled divided by the time:
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Explanation: If your values have dimensions like time, length, temperature, etc, then if the dimensions are not the same then the values are not the same. So a “dimensionally wrong equation” is always false and cannot represent a correct physical relation.
No, not necessarily.
For instance, Newton’s 2nd law is F=p˙ , or the sum of the applied forces on a body is equal to its time rate of change of its momentum. This is dimensionally correct, and a correct physical relation. It’s fine.
But take a look at this (incorrect) equation for the force of gravity:
F=−G(m+M)Mm√|r|3r
It has all the nice properties you’d expect: It’s dimensionally correct (assuming the standard traditional value for G ), it’s attractive, it’s symmetric in the masses, it’s inverse-square, etc. But it doesn’t correspond to a real, physical force.
It’s a counter-example to the claim that a dimensionally correct equation is necessarily a correct physical relation.
A simpler counter example is 1=2 . It is stating the equality of two dimensionless numbers. It is trivially dimensionally correct. But it is false.