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Vesna [10]
3 years ago
10

Solubility refers to the ability of a substance to dissolve in a solution. please select the best answer from the choices provid

ed t f
Chemistry
1 answer:
natima [27]3 years ago
6 0
Solubility is the property of the solute to dissolve itself in a solvent. The states of the solute and solvent may range from solid, liquid, and gas. Since the statement  above states a solution instead of a solvent. The answer is false.  solution is composed both of the dissoved solute and solvent.
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5. What is the systemic name for the following structure?
topjm [15]

Answer:

You are not showing the question, but I believe the answer is cis-3,4-dimethyl-3-hexene.

Explanation:

since the substituents are on same side, it call cis. Followed by the name.

5 0
3 years ago
_____ is the measurement of the density of a substance as compared to water.
alexgriva [62]
Answer: Specific gravity
8 0
3 years ago
What is the mass in grams of 2.0 moles of NO2
JulsSmile [24]
Molar mass NO₂ = 46.0 g/mol

1 mole -------- 46.0 g
2.0 moles ----- ?

Mass (NO₂) = 2.0 x 46.0 / 1

=> 92.0 g

hope this helps!
8 0
3 years ago
Read 2 more answers
Assuming equal concentrations and complete dissociation, rank these aqueous solutions by their freezing points. nh4cl cobr3 k2so
Illusion [34]
Answer: CoBr3 < K2SO4 < NH4 Cl

Justification:

1) The depression of the freezing point of a solution is a colligative property, which means that it depends on the number of particles of solute dissolved.

2) The formula for the depression of freezing point is:

ΔTf = i * Kf * m

Where i is the van't Hoof factor which accounts for the dissociation of the solute.

Kf is the freezing molal constant and only depends on the solvent

m is the molality (molal concentration).

3) Since, you are assuming equal concentrations and complete dissociation of the given solutes, the solute with more ions in the molecular formula will result  in the solution with higher depression of the freezing point (lower freezing point).

4) These are the dissociations of the given solutes:

a) NH4 Cl (s) --> NH4(+)(aq) + Cl(-) (aq) => 1 mol --> 2 moles

b) Co Br3 (s) --> Co(3+) (aq) + 3Br(-)(aq) => 1 mol --> 4 moles

c) K2SO4 (s) --> 2K(+) (aq) + SO4 (2-) (aq) => 1 mol --> 3 moles

5) So, the rank of solutions by their freezing points is:

CoBr3 < K2SO4 < NH4 Cl
4 0
3 years ago
Read 2 more answers
While heating up a 25 gram sample of concrete (specific heat = 0.210-cal/g°C), your initial tempărature is room temperature (25°
Lana71 [14]

Answer:

Final temperature  = 83.1 °C

Explanation:

Given data:

Mass of concrete = 25 g

Specific heat capacity = 0.210 cal/g. °C

Initial temperature = 25°C

Calories gain = 305 cal

Final temperature = ?

Solution:

Q = m. c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

ΔT = T2 - T1

305 cal = 25 g ×0.210 cal/g.°C × T2 -  25°C

305 cal = 5.25cal/°C × T2 -  25°C

305 cal / 5.25cal/°C = T2 -  25°C

58.1 °C = T2 -  25°C

T2 = 58.1 °C + 25°C

T2 = 83.1 °C

7 0
3 years ago
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