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gladu [14]
3 years ago
7

How many grams of a stock solution that is 92.5 percent H2SO4 by mass would be needed to make 250 grams of a 35.0 percent by mas

s solution? Show all of the work needed to solve this problem.
Chemistry
2 answers:
goldfiish [28.3K]3 years ago
6 0

M1m1 = M2m2

where M1 is the concentration of the stock solution, m1 is the mass of the stock solution, M2 is the concentration of the new solution and m2 is its new mass.

M1m1 = M2m2

.925(m1) = .35(250)

m1 = 94.59 g

tia_tia [17]3 years ago
3 0

Answer: 94.59 grams of 92.5 % H_2SO_4 by mass solution will be needed.

Explanation:

Mass of sulfuric acid is 250 grams of 35 % by mass solution:

35=\frac{x}{250 g}\times 100

x=87.5 g

Mass of H_2SO_4 in 250 g of 35 % solution = 87.5 g

Mass of 92.5 % H_2SO_4 needed to make 35 % by mass solution.

92.5=\frac{87.5 g}{\text{mass of the solution required}}\times 100

Mass of the solution required = 94.59 g

94.59 grams of 92.5 % H_2SO_4 by mass solution will be needed.

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