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dybincka [34]
3 years ago
14

Bonus:#1,Dancy placed 57 bags of rice weighing a total of 54.72 pounds on 3 shelves. If she divides tye bags equally on each she

lf,how much weight would each shel f hold
Mathematics
1 answer:
lapo4ka [179]3 years ago
3 0
18.24 pounds on each shelf because the weight divided by the amount of bags would be .96 pounds per bag. And then the total amount of bags divided by the amount of shelves would be 19 so 19x.96 pounds is 18.24 on each shelf
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(7,0), endpoint (3,-4)
mafiozo [28]

Answer:

11,4 is the answers for the question

Step-by-step explanation:

please give me brainlest and follow me

3 0
3 years ago
A stand is a frustum shape, formed by removing a small square-based pyramid from the top of
kupik [55]

The frustum can be considered as consisting of a square pyramid, less the

cut volume.

  • The mass of the stand, is approximately 18.60905 kg

Reasons:

The given parameter of the frustum are;

The density of the frustum, ρ = 85 g/cm³

Height of pyramid, h = 9 cm

Side length of base = 10 cm

Height of frustum

By proportional shapes, the side length of the top of the frustum can be found as follows;

\dfrac{4 \, cm}{9 \, cm} = \dfrac{x}{10 \, cm}

x = \dfrac{4 \, cm}{9 \, cm} \times 10 \, cm = 4\frac{4}{9} \, cm

V = \dfrac{h}{3} \times \left(B_1 + B_2 + \sqrt{B_1 \times B_2} \right)

B₁ = 10², B₂ = \left(4\frac{4}{9} \right)^2

Therefore;

V = \dfrac{4}{3} \times \left(10^2 + \left(4\frac{4}{9}  \right)^2  + \sqrt{10^2 \times  \left(4\frac{4}{9}  \right)^2} \right) \approx 218.93

The volume of the stand, V ≈ 218.93 cm³

Mass = Volume × Density

∴ Mass of the stand, m = 218.93 cm³ × 85 g/cm³ = 18,609.05 grams = 18.60905 kg.

Learn more here:

brainly.com/question/24323975

8 0
3 years ago
Can someone please help me? thanks!
iragen [17]
The small rectangle was blown up by 5 times to turn into the bigger rectangle to put x5 in the box =)
8 0
3 years ago
Read 2 more answers
Equation of a circle whose center is at (4,0) and radius is length 2/3
Masteriza [31]
We need (x-h)^2 + (y-k)^2 = r^2

h = 4, k = 0 and r = 2/3

Take it from here.
5 0
3 years ago
A 273,000-gallon shipment of fuel is 2.3 percent
-Dominant- [34]

Answer:

Amount of fuel antifreeze = 6,279 gallon

Step-by-step explanation:

Given:

Amount of fuel =  273,000-gallon

Antifreeze = 2.3 %

Find:

Amount of fuel antifreeze

Computation:

Amount of fuel antifreeze = Amount of fuel × Antifreeze

Amount of fuel antifreeze = 273,000 × 2.3 %

Amount of fuel antifreeze = 6,279 gallon

8 0
4 years ago
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