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Phoenix [80]
3 years ago
13

Which reaction is an example of an oxidation-reduction reaction?

Chemistry
2 answers:
d1i1m1o1n [39]3 years ago
8 0

Answer:

4.

Explanation:

sineoko [7]3 years ago
4 0
1st one is, and second one is
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Noin
OLga [1]

Answer:

Gravity is the answer.

5 0
2 years ago
How many grams will be produced
Anni [7]

Answer:

\Large \boxed{\sf 34.2 \ g}

Explanation:

Mole ratio

9:4

1.75:x

Moles of CO₂

\displaystyle \frac{4 \times 1.75}{9} =0.78

Use formula to find mass

\displaystyle moles=\frac{mass}{M_r}

Relative molecular mass of CO₂ = 12 + 16 × 2 = 44

\displaystyle 0.78=\frac{mass}{44}

mass=34.2

4 0
2 years ago
The balanced equation for combustion in an acetylene torch is shown below:
vichka [17]

Answer:

70mol

Explanation:

The equation of the reaction is given as:

                  2C₂H₂ + 5O₂ → 4CO₂ + 2H₂O

Given parameters:

Number of moles of acetylene = 35.0mol

Number of moles of oxygen in the tank = 84.0mol

Unknown:

Number of moles of CO₂ produced = 35.0mol

Solution:

From the information given about the reaction, we know that the reactant that limits this combustion process is acetylene. Oxygen is given in excess and we don't know the number of moles of this gas that was used up. We know for sure that all the moles of acetylene provided was used to furnish the burning procedure.

To determine the number of moles of CO₂ produced, we use the stoichiometric relationship between the known acetylene and the CO₂ produced from the balanced chemical equation:

From the equation:

         2 moles of acetylene produced 4 moles of CO₂

          ∴ 35.0 mol of acetylene would produced:  

                               \frac{35 x 4}{2} = 70mol

6 0
2 years ago
Read 2 more answers
How many particles are in 23 g of H 2 O?
Sedaia [141]
1 mole of any substance contains 6.022 × 1023 particles.

⚛ 6.022 × 1023 is known as the Avogadro Number or Avogadro Constant and is given the symbol NA

N = n × NA

· N = number of particles in the substance

· n = amount of substance in moles (mol)

· NA = Avogardro Number = 6.022 × 10^23 particles mol-1


For H2O we have:

2 H at 1.0 each = 2.0 amu
1 O at 16.0 each = 16.0 amu
Total for H2O = 18.0 amu, or grams/mole

It takes 18 grams of H2O to obtain 1 mole, or 6.02 x 1023 molecules of water. Think about that before we answer the question. We have 25.0 grams of water, so we have more than one mole of water molecules. To find the exact number, divide the available mass (25.0g) by the molar mass (18.0g/mole). Watch how the units work out. The grams cancel and moles moves to the top, leaving moles of water. [g/(g/mole) = moles].

Here we have 25.0 g/(18.0g/mole) = 1.39 moles water (3 sig figs).

Multiply 1.39 moles times the definition of a mole to arrive at the actual number of water molecules:

1.39 (moles water) * 6.02 x 1023 molecules water/(mole water) = 8.36 x 1023 molecules water.

That's slightly above Avogadro's number, which is what we expected. Keeping the units in the calculations is annoying, I know, but it helps guide the operations and if you wind up with the unit desired, there is a good chance you've done the problem correctly.

N = n × (6.022 × 10^23)


1 grams H2O is equal to 0.055508435061792 mol.

Then 23 g of H2O is 1.2767 mol


To calculate the number of particles, N, in a substance:

N = n × NA

N = 1.2767 × (6.022 × 10^23)

N= 176.26

N=
3 0
2 years ago
An independent variable is....
Irina18 [472]

Answer:

B - What we change

Explanation:

Dependent Variable - What we measure

Control Variable - what stays the same

Conclusion - what we conclude

<em>Hope</em><em> </em><em>this</em><em> </em><em>can</em><em> </em><em>Help</em><em>!</em>

<em>:</em><em>D</em>

5 0
2 years ago
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