Two round concentric metal wires lie on a tabletop, one inside the other. The inner wire has a diameter of 23.0 and carries a cl
1 answer:
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Answer:
Part A:
Part B:
Explanation:
Part A:
Formula of Electric Field Strength:
Where:
x is the distance from the ring
R is the radius of the ring
is constant permittivity of free space=8.854*10^-12 farads/meter
Q is the charge
For right Ring E at the midpoint can be calculated as:
x for right plate=25/2=12.5 cm=0.125 m
Radius=R=10/2=5 cm=0.05 m
For Left Ring E at the midpoint can be calculated as:
Since charge on both plates is +ve and same in magnitude, the electric field will be same for both plates.
Electric Field at midpoint:
Both rings have same magnitude but the direction of fields will be opposite as they have same charge on them.
Part B:
At center of left ring:
Due to left ring Electric field at center is zero because x=0.
Due to right ring Electric field at center of left ring:
Now: x=25 cm= o.25 m (To the center of left ring)
Electric Field Strength at center of left ring is same as that of right ring.
Answer: (d)
Explanation:
Given
Mass of object
Speed of object
Mass of object at rest
Suppose after collision, speed is v
conserving momentum
Initial kinetic energy
Final kinetic energy
So, it is clear there is decrease in kinetic energy . Thus, energy decreases and velocity becomes 2 m/s.
The distance covered is 115 m
Explanation:
The motion of Ileana is a uniformly accelerated motion (constant acceleration), therefore we can use the following suvat equation:
where
s is the distance covered
u is the initiaal velocity
v is the final velocity
t is the time elapsed
In this problem, we have:
u = 4.20 m/s
v = 5.00 m/s
t = 25.0 s
Therefore, we can re-arrange the equation to find the distance covered:
Learn more about accelerated motion:
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