An osmolarity of saline solution is 308 mosmol/L.
m(NaCl) = 9 g; the mass of sodium chloride
V(solution) = 1 L; the volume of the saline solution
n(NaCl) = 9 g ÷ 58.44 g/mol
n(NaCl) = 0.155 mol; the amount of sodium chloride
number of ions = 2
Osmotic concentration (osmolarity) is a measure of how many osmoles of particles of solute it contains per liter.
The osmolarity = n(NaCl) ÷ V(solution) × 2
The osmolarity = 0.154 mol ÷ 1 L × 2
The osmolarity = 0.154 mol/L × 1000 mmol/m × 2
The osmolarity of the saline solution = 308 mosm/L.
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Answer:
The volume of the second cylinder is 80 liters
Explanation:
We use the Boyle-Mariotte formula, according to which the pressure and volume of a gas are inversely related, keeping the temperature constant: P1 x V1 = P2xV2. We convert the pressure in mmHg to atm:
760 mmHg-----1 atm
380mmHg------x= (380mmHgx1atm)/760mmHg=0,5 atm
P1xV1=P2xV2
2 atmx20 L= 0,5atm x V2 V2=(2 atmx20 L)/0,5atm=80L
That would be C. Organelles
Answer:
Here,
0.01040 m as an integer= 1.04 × 10-2
