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zzz [600]
3 years ago
6

What happens to a wave when it moves from one medium to another?

Physics
1 answer:
Nina [5.8K]3 years ago
3 0
One side of the wave changes speed before the other side, causing the wave to move
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A sample of a diatomic ideal gas has pressure P and volume V. When the gas is warmed, its pressure triples and its volume double
Andreyy89

Answer:

Amount of  Energy transferred =8.5PV

Explanation:

Given:

Initial volume=V

Initial pressure=P

Final volume=2V

Final pressure=3P

Now w know that the Energy transferred in constant pressure pressure is given by

E_1=nc_pdT\\\\E_1=n\times\dfrac{7R}{2}dT\\E_1=3.5(nRdT)\\E_1=3.5(V(2P-P))\\E_1=3.5PV

Now the Energy transferred in constant volume process is given by

E_2=nc_vdT\\\\E_2=n\times\dfrac{5R}{2}dT\\E_1=2.5(nRdT)\\E_1=2.5(V(3V-V))\\E_1=5PV

The total Energy transferred is given by

E_{total}=E_1+E_2\\E{total}=3.5PV+5PV\\=8.5PV

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3 years ago
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How to find the area of the side with the maximum surface area of a rectangle
Aleks04 [339]

Answer:

Let one side = Let the other side= Let area = Let perimeter= Now substitute into area formula

Explanation:

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3 years ago
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1. Molly carries a 30 kg bag of feed up a ramp which has a base of 4 m and a height of 2 meters. How
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it is b. 588 Nm

Explanation:

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Which of the following describes the way a population can be dispersed?
zubka84 [21]

Answer:

option b. <em>uniform</em><em> </em><em>population</em>

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Suppose you stand with one foot on ceramic flooring and one on a wool carpet, making contact over a 77.2 cm2 area with each foot
Finger [1]

Answer:

P_{c= 5.74W

P_{w}=0.27 W

Explanation:

d= 2.6cm =>0.026m (for both the ceramic and the carpet )

Thermal conductivity of wool 'k_{w}'= k_{carpet} = k_{wool}=  0.04J/(sm °C)

Thermal conducticity of carpet 'k_c}' = 0.84 J/(sm °C)

Area 'A'= A_{carpet}= A_{ceramic}= 77.2cm²=> 77.2 x 10^{-4}m²

T_h}=33.0°C

T_c}=10.0°C

Average Power P_{avg} is determined by dividing amount of energy'Q' by time taken for the transfer't':

P_{avg} = Q/Δt

Due to conductivity, heat of flow rate will be P= dQ/dt

P=\frac{dQ}{dt} = \frac{kA[T_{h}-T_{c} ]}{d}

For CERAMIC:

P_{c=\frac{k_{c} A[T_{h}-T_{c} ]}{d} => [0.84 x 77.2 x 10^{-4}(33-10) ]/0.026

P_{c= 5.74W

For WOOL CARPET:

P_{w}= \frac{k_{w} A[T_{h}-T_{c} ]}{d}=> [0.04 x 77.2 x 10^{-4}(33-10) ]/0.026

P_{w}=0.27 W

8 0
3 years ago
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