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3 years ago

The plant on the left is growing more because it has been receiving more water.

Chemistry

1 answer:

antiseptic1488 [7]3 years ago

8 0

Answer:

Learning Task 2: Read the passage, then answer the questions that follow. Write your answers in your notebook. Have you seen Mount Banahaw and Mount Makiling? These are the two important land features in CALABARZON. They are both magnificent in terms of their flora and fauna. They provide nesting place to great species that are uniquely available in their systems. They are also considered mystical. Both mountains provide great source of water to locals. They are surrounded by nearby hot springs. Hot Springs near Mount Makiling can be found in Pansol area while hot spring near Mount Banahaw is located in Tayabas City 1. What are the two figures or icons portrayed in the selection? 2. Are they similar? Describe the features of the two. 3. Are there differences between the two? Explain their dissimilarities. 4. What structure of text-type is employed in the selection?

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The freezing point of diet soda is higher than the freezing point of regular soda, but lower than 0 degrees celcius, the freezin

Zepler [3.9K]

Answer:

Explanation:

Both Diet Soda and regular soda contain sweeteners.

When a solute is dissolved in solution, the solution undergoes *freezing point depression* it freezing point reduces. The magnitude of freezing point depression is directly proportional to the amount of solute in a solution.

Since soda Both regular or diet soda contains more solute than water , their freezing point is will consequently be lower than water

4 0

2 years ago

Identify the solute with the highest van't Hoff factor. And how do you determine which one is highest?

german

Answer : The correct option is, (A) $AlCl_3$

Explanation :

Van't Hoff factor : It is defined as the ratio of the experimental value of the colligative property to the calculated value of the colligative property.

We can determine the van't Hoff factor by the association and dissociation of the compound.

(A) $AlCl_3$

It is an electrolyte that dissociates to give aluminum ion and chloride ion.

The dissociation of $AlCl_3$ will be,

$AlCl_3\rightarrow Al^{3+}+3Cl^{-}$

So, Van't Hoff factor = Number of solute particles = $Al^{3+}+3Cl^{-}$ = 1 + 3 = 4

(B) $KI$

It is an electrolyte that dissociates to give potassium ion and iodide ion.

The dissociation of $KI$ will be,

$KI\rightarrow K^{+}+I^{-}$

So, Van't Hoff factor = Number of solute particles = $K^{+}+I^{-}$ = 1 + 1 = 2

(C) $CaCl_2$

It is an electrolyte that dissociates to give calcium ion and chloride ion.

The dissociation of $CaCl_2$ will be,

$CaCl_2\rightarrow Ca^{2+}+2Cl^{-}$

So, Van't Hoff factor = Number of solute particles = $Ca^{2+}+2Cl^{-}$ = 1 + 2 = 3

(D) $MgSO_4$

It is an electrolyte that dissociates to give magnesium ion and sulfate ion.

The dissociation of $MgSO_4$ will be,

$MgSO_4\rightarrow Mg^{2+}+SO_4^{2-}$

So, Van't Hoff factor = Number of solute particles = $Mg^{2+}+SO_4^{2-}$ = 1 + 1 = 2

(E) Non-electrolyte

The dissociation non-electrolyte is not possible. So, the Van't Hoff factor will always be, 1.

Hence, the highest van't Hoff factor of solute is, $AlCl_3$

7 0

3 years ago

Based on the electron configuration of the two

Whitepunk [10]

Answer:

Explanation:

Cuz the when you pair Li and Cl, it becomes LiCl (it has 1:1 ratio)

4 0

3 years ago

Read 2 more answers

What is the relationship between the Kuiper Belt and the status of Pluto today?

Xelga [282]

Pluto is a dwarf planet, but one of the largest known members, in the Kuiper belt.

The Kuiper Belt extends between 30 AU and 55 AU from the Sun

(1 AU = 1.5 × 10^8 km = distance from Earth to Sun).

Pluto's orbit is highly elliptical. It ranges from 30 AU to 50 AU. When Pluto is closest to the Sun, it is inside the orbit of Neptune (30 AU).

Astronomers class Pluto as a <em>resonant Kuiper belt object</em> (KBO). Because it gets so close to Neptune, its orbit is in <em>resonance</em> with that of Neptune. Pluto makes two orbits for every three of Neptune.

4 0

3 years ago

Convert 1 bromopropane to bromoethane.

Dovator [93]

Answer:

The Dehydrohaogenation of 1-bromo propane with alcoholic KOH gives propene which on again hydrohalogenation with HBr gives 2-bromo propane due to Markonikove's rule for addition.

Explanation:

6 0

2 years ago