Find a number you can multiply by the bottom of the fraction to make it 10, 100, or 1000 and multiple both top and bottom by that number then write down just the top number putting the decimal point in the correct spot.
F=ir^t
139=134r^10
139/134=r^10
r=(139/134)^(1/10) then:
f=134(139/134)^(t/10) so in 2014, t=24 so
f=134(139/134)^(2.4)
f≈146 million (to nearest million)
Some will say that you have to use the exponential function, but it really gives you the same answer...even for continuous compounding :)...
A=Pe^(kt)
139=134e^(10k)
139/134=e^(10k)
ln(139/134)=10k
k=ln(139/134)/10 so
A=134e^(t*ln(139/134)/10) when t=24
A=134e^(2.4*ln(139/134))
A≈146 million (to nearest million)
The only real reason or advantage to using A=Pe^(kt) is when you start getting into differential equations...
Answer:
60
Step-by-step explanation:
The computation of the rest of the marbles is given below:
Since there is 20 red and 15 white marbles
Also the 3 bags contains same marbles
So if he gives 45 marbles, so the remaining would be
= (20 + 15) × 3 - 45
= 35 × 3 - 45
= 105 - 45
= 60
