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iogann1982 [59]
3 years ago
9

A man is standing on a platform that is connected to a pulley arrangement, as the drawing shows. By pulling upward on the rope w

ith a force the man can raise the platform and himself. The total mass of the man plus the platform is 113 kg. What pulling force should the man apply to create an upward acceleration of 1.20 m/s2?

Physics
1 answer:
leonid [27]3 years ago
8 0

Answer:

The pulling force that the man should apply to create an upward acceleration of 1.20m/s^{2} is P=621.5N

Explanation:

Hi

As it shows in the drawing at the end, we have that the total mass of the man plus the platform is 113 kg, then the force downward W is W=mg=113Kg*9.8m/s^{2}=1107.4N.

Due the man needs to do a pulling force upward capable of lifting himself and the platform with an acceleration of 1.20m/s^{2}, this force should create an acceleration greater than gravity by 1.20m/s^{2}. then a_{up}=g+1.2m/s^{2}=9.8m/s^{2}+1.2m/s^{2}=11m/s^{2}. Therefore the force should be P_{up}=ma_{up}=113kg*11m/s^{2}=1243N.

Finally, as we have a pulley arrangement connected to the platform, it gives the man a mechanical advantage, so he has to do only half of that upward force

, therefore P=\frac{1243N}{2}=621.5N.

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An astronaut rides in a circular training accelerator at 16 m/s. If the radius of the accelerator is 8.0 meters, what is his cen
iren [92.7K]

Answer:

a=32\ m/s^2

Explanation:

Given that,

The velocity of an astronaut in a circular path, v = 16 m/s

The radius of the accelerator, r = 8 m

We need to find his centripetal acceleration. The formula that is used to find the centripetal acceleration is given by :

a=\dfrac{v^2}{r}\\\\a=\dfrac{(16)^2}{8}\\\\a=32\ m/s^2

So, the required centripetal acceleration is 32\ m/s^2.

7 0
3 years ago
Hole filling fasteners (for example, MS20470 rivets) should not be used in composite structures primarily because of the?
DIA [1.3K]

Answer:

We can cause delamination.

Explanation:

The reason why is because the probability of causing delamination increase considerably when we use Hole-filling fasteners. If we use a typical rivet, these tends to expands in order to fill the hole.

If we analyze the force applied by the expanded rod will cause that the matrial will be deteriorated and will cause that the material to delaminate around the edges of the hole and we can cause possible control and no protection to the material.

7 0
3 years ago
Jake drags a sled of mass 25 kg across the snow. The sled is attached to a rope that pulls with a force of 50 N at an angle of 3
madam [21]

Answer:

218.5 N

Explanation:

In order for the sled to be in equilibrium along the vertical direction, the forces acting along this direction must be balanced. So the equilibrium equation is:

N+F sin \theta - mg =0

where

N is the normal force

F = 50 N is the force that pulls the sled

\theta is the angle between the force and the horizontal, so

F sin \theta is the component of F acting along the vertical direction

(mg) is the weight of the sled, with

m = 25 kg being the mass of the sled

g = 9.8 m/s^2 is the acceleration due to gravity

Solving the formula for N, we find

N=mg-F sin \theta = (25 kg)(9.8 m/s^2)-(50 N)sin 32^{\circ}=218.5 N

7 0
3 years ago
A 4 kg textbook sits on a desk. It is pushed horizontally with a 50 N applied force against a 15 N frictional force.
GarryVolchara [31]

a) See free-body diagram in attachment

b) The book is stationary in the vertical direction

c) The net horizontal force is 35 N in the forward direction

d) The net force on the book is 35 N in the forward horizontal direction

e) The acceleration is 8.75 m/s^2 in the forward direction

Explanation:

a)

The free-body diagram of a body represents all the forces acting on the body using arrows, where the length of each arrow is proportional to the magnitude of the force and points in the same direction.

From the diagram of this book, we see there are 4 forces acting on the book:

- The applied force, F = 50 N, pushing forward in the horizontal direction

- The frictional force, F_f = 15 N, pulling backward in the horizontal direction (the frictional force always acts in the direction opposite to the motion)

- The weight of the book, W=mg, where m is the mass of the book and g=9.8 m/s^2 is the acceleration of gravity, acting downward. We can calculate its magnitude using the mass of the book, m = 4 kg:

W=(4)(9.8)=39.2 N

- The normal reaction exerted by the desk on the book, N, acting upward, and balancing the weight of the book

b)

The book is in equilibrium in the vertical direction, therefore there is no motion.

In fact, the magnitude of the normal reaction (N) exerted by the desk on the book is exactly equal to the weight of the book (W), so the equation of motion along the vertical direction is

N-W=ma

where a is the acceleration; however, since N = W, this becomes

a=0

And since the book is initially at rest on the desk, this means that there is no motion.

c)

We said there are two forces acting in the horizontal direction:

- The applied force, F = 50 N, forward

- The frictional force, F_f = 15 N, backward

Since they act along the same line, we can calculate their resultant as

\sum F = F - F_f = 50 - 15 = 35 N

and therefore the net force is 35 N in the forward direction.

d)

The net force is obtained as the resultant  of the net forces in the horizontal and vertical direction. However, we have:

- The net force in the horizontal direction is 35 N

- The net force in the vertical direction is zero, because the weight is balanced by the normal reaction

Therefore, this means that the total net force acting on the book is just the net force acting on the horizontal direction, so 35 N forward.

e)

The acceleration of the book can be calculated by using Newton's second law:

\sum F = ma

where

\sum F is the net force

m is the mass

a is the acceleration

Here we have:

\sum F = 35 N (in the forward direction)

m = 4 kg

Therefore, the acceleration is

a=\frac{\sum F}{m}=\frac{35}{4}=8.75 m/s^2 (forward)

Learn more about forces, weight and Newton's second law:

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brainly.com/question/12978926

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brainly.com/question/2286502

brainly.com/question/2562700

#LearnwithBrainly

8 0
4 years ago
A refrigerator receives 240 V of electricity. If it uses 32 A of current, what is the resistance of the refrigerator?
Leokris [45]

\mathfrak{\huge{\orange{\underline{\underline{AnSwEr:-}}}}}

Actually Welcome to the Concept of the Ohms Law,

According to the Ohms law,

V = I*R, where, V = Voltage, I = Current, R = resistance,

so here given as, V = 240 V, I = 32 A,

so we get as, R = 240/32

R = 7.5 ohms,

===> The resistant R is ==> 7.5 ohms.

7 0
3 years ago
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